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9 answers

% solutions are #grams per 100 mL.

So 75 grams in 500 mLs would be:
>>>There are 5 x 100mL
>>> 75/5 = 15

Your solution is a 15% solution.

2006-08-23 06:07:16 · answer #1 · answered by BugsBiteBack 3 · 0 0

Mmm
Notice that you can only make this operation exact, if you are working with water solutions, beacause amls of water weights exactly 1 gram (under normal conditions of temp. and pressure)
Then if is the case, the solution you want has 575 grams of total mass, so the percent of thew solid is: 75 *100/575 =13.043478260869565217391304347826% more or less

2006-08-23 06:23:53 · answer #2 · answered by Christian C 6 · 0 0

in case you may not determine those out devoid of information, i do no longer desire you allotting meds. C'mon. If there is a hundred twenty five mg of ampicillin in a 5 ml dose, isn't it obvious which you desire 4 a hundred twenty five mg doses - and for that reason 20 ml of answer - as a fashion to get 500 mg of ampicillin? you may not upload up ninety 5 milliliters, a million.8 liter, 365 milliliters and a pair of/5 of a liter? hint: how many milliliters are there in a liter? perchance you need to be taking training for hod donning, as a exchange?

2016-12-14 10:25:39 · answer #3 · answered by Anonymous · 0 0

75 mg in 500 mL, by dividing both by 5, translates to 15 mg per 100 mL.

% solution is % w/v and is grams/100 mL.

So 15 mg/100 mL is 0.015 g/100 mL or 0.015% w/v

2006-08-23 06:23:58 · answer #4 · answered by david_s_ca 2 · 0 0

The first answer is correct assuming that the 500mls refers to the volume AFTER you have added the drug. Otherwise, it would be more like a 13% solution.

2006-08-23 06:10:23 · answer #5 · answered by Graham I 6 · 0 0

1 g per ml is 100% w/v (weight per volume).

75g/500ml * 100 = ahh I don't have a calculator %

weight/ volume * 100.

2006-08-23 06:11:49 · answer #6 · answered by Ellie 4 · 0 0

buy a nurses calculation book and work it out

2006-08-23 06:10:04 · answer #7 · answered by sky 4 · 0 0

divide it by 5, and you have a percentage

2006-08-27 03:47:10 · answer #8 · answered by Anonymous · 0 0

Please see the webpage for more details on Concentration (Molarity).

2006-08-25 23:10:51 · answer #9 · answered by gangadharan nair 7 · 0 0

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