how would you work this problem
2006-08-23 04:27:53 · 3 answers · asked by iluvhipos 3 in Education & Reference ➔ Other - Education
The answer is 324*a^2*b^8.
I think the binomial expansion comes into play here. There is some formula for specific terms which would be contained in an excellent calculus textbook.
You could also visit the online Mathematica site at www.wolfram.com
(a+b)^n = a^n + ... + b^n
2006-08-23 04:30:41 · answer #1 · answered by Anonymous · 0⤊ 0⤋
6,561a^8+a million,749a^7b that is persisted from down there +20,412a^6b^2+13,608a^5b^3 that is persisted from down there +5,607a^4b^4+1512a^3b^5+ that is persisted from down there 252a^2b^6+24ab^7+b^8
2016-11-27 00:40:09 · answer #2 · answered by ? 4 · 0⤊ 0⤋
The answer is 27ab^8
Oops, nope, that is the 9th term.
2006-08-23 04:35:50 · answer #3 · answered by Will 4 · 0⤊ 2⤋