if i wire a 2mH inductor and 2mF capacitor in series with a 5V power suppy @ 75.5Hz what is the current?
Ill post the answer in about 30 min
2006-08-23 03:47:43 · 8 answers · asked by john 3 in Science & Mathematics ➔ Engineering
ahem...CURRENT
2006-08-23 04:00:18 · update #1
ok ill give a hint you need to find reactance
2006-08-23 04:01:53 · update #2
ok maybe this is too hard, 1/ (2 pi F C) is capacitive reactance and 1/ (2 pi F L) is inductive
2006-08-23 04:04:14 · update #3
the anwer is Infinity
The ciruit is at resonace, so the resistance is 0
2006-08-23 04:11:36 · update #4
The resonant frequency (calculated in MathCad) for this circuit is 79.6Hz
2006-08-23 15:31:50 · answer #1 · answered by gp4rts 7 · 0⤊ 0⤋
Using the formula for impedance in a series LC circuit, Z = j*(w^2*LC - 1)/(wC), which comes out to -6.47j. I think the presence of j means a 90 degree phase shift. So I = V/Z = 5*sin(75.5)/-6.47j = 0.77*cos(75.5).
This circuit is not at resonance. The resonant frequency is sqrt(1/LC) = sqrt(1/4e-6) = 500 Hz.
2006-08-23 04:15:21 · answer #2 · answered by DavidK93 7 · 0⤊ 0⤋
About 6 microvolts
2006-08-23 03:58:30 · answer #3 · answered by Amphibolite 7 · 0⤊ 1⤋
Let s=2*pi*f
Then Z = (s*2*10^-3) + (s*2*10^-3)^-1
I = V / Z
plug and chug.
hope you do well on your homework.
2006-08-23 04:00:49 · answer #4 · answered by cw 3 · 0⤊ 0⤋
David is correct in that this circuit is not in resonance, but he did not convert his frequency to radians so don't believe his answer. I got 47.6
2006-08-23 04:35:38
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answer #5
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answered by alethiaxx 3
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The current is approximately x, where x=current.
2006-08-23 04:12:57 · answer #6 · answered by Anonymous · 0⤊ 0⤋
What is teh resitance ?
2006-08-23 23:24:19 · answer #7 · answered by Ali 2 · 0⤊ 0⤋
5.84526 microvolts it is fr sure!!
and 2.67 amperes as my calculator says!!!
LOL
2006-08-23 03:59:23 · answer #8 · answered by BrainCracker 4 · 0⤊ 1⤋