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I want to replace the existing tile with new tile - without taking up the old. I've been told I can retile over the existing. Is this a good way of doing it?

2006-08-23 02:29:51 · 4 answers · asked by Betty m 1 in Home & Garden Decorating & Remodeling

4 answers

yes you can do that my mom had it done. But i dont know if its the best way because if you decide to change you mind later years down the line the other person got to do more work.

2006-08-23 02:33:26 · answer #1 · answered by justme 3 · 0 0

Hi we're considering the same way for our bathroom & friends of mine for his.

This is what we've come up with however, again, should go to a flooring place or more net research to make sure.

Bascially fill in the areas with grout so you have one huge flat surface.

Then with the proper glue & tiles you can cover this.

Apparently its not a huge issue to remove tiles--just a lot of hard work, you need a hammer & a chisel but its doable--and a sander to sand off the old stuff from the floor

Then you need to vaccum it really well, clean it down with TSP or vinager and water mixture.

And remove every single dust, etc. From ppl who've done this--they tell me that's the the hardest part.

After this, you apply the correct glues and tiles and there you go--a new floor.

2006-08-23 02:43:50 · answer #2 · answered by belligerent assistant 5 · 0 0

Definitely visit a flooring store and browse through the vinyl tiling - we replaced our old rolled vinyl flooring with large 12" vinyl tiles and grout - so pretty, much more comfortable than ceramic and low maintenance...
Good luck...

2006-08-23 02:36:57 · answer #3 · answered by Anonymous · 0 0

You don't mention if it is ceramic tile, vinyl tile or whatever, and the answer is different depending on what kind.

In general, if you tile over ceramic with more ceramic, you risk the subfloor not being able to support it. I'd say the only thing I'd try is vinyl over ceramic if the ceramic is simply discolored and not damaged.

2006-08-23 02:34:55 · answer #4 · answered by nora22000 7 · 0 0

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