Excellent question... not enough people know about these guys. They think Mike Tyson and Oscar De Lahoya invented boxing.
I am assuming that "in their prime" means they would be fighting at light heavyweight. Although Bob Foster was one of the best KO artists at that weight, I am going with the Old Mongoose Archie Moore. I believe he was an excellent defensive fighter who could also punch very hard. He also was a bit more succsesful at taking heavyweight punches (although just as Foster, he did not win a heavyweight title).
I think the longer the fight went, the less of a chance Foster would have of winning.
Moore by late TKO.
2006-08-22 00:08:23
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answer #1
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answered by capt.jeepman 2
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Archie Moore
2006-08-21 20:06:05
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answer #2
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answered by christine w 2
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The Mongoose wins! Archie Moore was arguably the best Light Heavyweight ever. Foster was good, but Archie was the Man!
2006-08-22 03:06:06
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answer #3
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answered by Adios 5
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Foster - W 56 (KO's 46) TF 65 - W pct 86% - KO pct 71% - wins over D. Tiger, V. Rondon and M. Quarry - KO'ed by Frazier and Ali (all his KO defeats were by Hwy wts except 2 at the end of his career when he was 40 yrs old) - #17 ranked puncher - #55 ranked fighter
Moore - W 187 (KO's 132) TF 222 - W pct 84% - KO pct 59% - wins over Durrell, B. Satterfield and H. Johnson - KO'ed by Ali, Marciano, Patterson and E. Charles - #4 ranked puncher - #14 ranked fighter
This is fight between #1 Lighthwy wt and possibly the #2 Lighthwy wt. This would not be as easy a fight for Moore than everyone thinks. Moore will have to get up off the canvas on numerous occasions to KO Foster in the 12th rd.
2006-08-23 12:17:37
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answer #4
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answered by smitty 7
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Archie Moore.
2006-08-22 07:08:20
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answer #5
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answered by Anonymous
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Archie Moore was the greatest lt heavy champ of all time, Moore wins by KO in round 10
2006-08-22 10:12:56
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answer #6
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answered by The Duke 3
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Moore TKO round 12
2006-08-22 02:38:36
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answer #7
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answered by Brent 5
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archie moore a true heavyweight. foster is not. but a great dream fight .
2006-08-21 22:50:19
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answer #8
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answered by Anonymous
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