Simplify (9x^2y^3z-12xy^2z^2)/3yz?
read it as 9 x to the second y to the third z minus 12 x y to the second divided by 3 yz.
I got 3 x to the second y to the second minus 4 x y z.
And yes I did ask this question in "mathematics"?And I didn't get any takers.
Cmon,ppl.Help Pancha out!
2006-08-21 13:41:34 · 13 answers · asked by Anonymous in Politics & Government ➔ Immigration
It's not HOMEWORK!!!!Check my math ,dammit!
2006-08-21 13:48:45 · update #1
Hey,I didn't shout!I asked nicely for someone to answer my que,dammit!
2006-08-21 13:51:33 · update #2
Then answer ,pinche banidido!
2006-08-21 13:52:25 · update #3
THAT what to ENGLISH!
2006-08-21 13:53:30 · update #4
ROB! ROB! Your not helping MAN!!!!!!
But seriously......thanks.
2006-08-21 15:17:07 · update #5
That can be two way different things....or 3 actually...maybe 4 or 5 depending on what exactly the equasion is being divided into.
That can either be nine x to second y to third z minus twelve times x times y to second z to the second divided by 3 times y times z
or nine x to the second y to the third z minus twelve x y to the second z to the second divided by 3 times y times z or just divided by 3 y z..
On all of my answers, I didn't get anywhere near 3x^2y^2-4xyz
Remember, that each variable is the same meaning, 3x and 4x... x is the same variable, so it needs to be simplified. And by doing that, it must go to the first number.. or actually the first side of the equasion. ie: the left, unless using scientific negotiation(s) in quadratic equasions or the such, --OR-- specifying the configuration accordingly by using operational sigma's to indicate standard plus or minus diviations....
Here's an example...
A model of the quantity.. in question by a normal distribution and estimate lower and upper limits:
a- and a+ such that the best estimated value of the quantity is (a+ + a-)/2 (i.e., the center of the limits) and there is 1 chance out of 2 (i.e., a 50 percent probability) that the value of the quantity lies in the interval a- to a+. Then uj 1.48 a where a = (a+ - a-) /2 is the half-width of the interval.
That's a new subject though and I'm getting off track...okay, so your question...
Here is as follows, periods are spacing only:
..........( 9x^2y^3z - 12xy )....... ( 81xy^3z - 12xy )
....... - - - - - - - - - - - - - - = - - - - - - - - - - - - - - -
.................... 3yz . . . . . .. . . . . . . . 3yz
.......... ( 81xy^3z - 12xy )....... ( 531,441xyz - 12xy )
....... - - - - - - - - - - - - - - - = - - - - - - - - - - - - - - -
.....................3yz . . . . . . . . . . . . . . . 3yz
.......... (531,441xyz - 12xy)
....... - - - - - - - - - - - - - - - - = 177,143x^2y^3z^2
.....................3yz
However, I highly doubt that was the answer to that...unless you made it up.
So, I'll do the other choice-- the one that a textbook might have:
........( 9x^2 * y^3 * z - 12xy )......( 81 * y^3 * z - 12xy )
...... - - - - - - - - - - - - - - - - - = - - - - - - - - - - - - - - - -
.................... 3yz ......................... . . .. 3yz
........ ( 81 * y^3 * z - 12xy )....... ( 81y^3 * z - 12xy )
...... - - - - - - - - - - - - - - - - - = - - - - - - - - - - - - - - -
.................... 3yz.............. . . . . . . . ... 3yz
........ ( 81y^3 * z - 12xy ) ....... ( 81y^3z -12xy )
...... - - - - - - - - - - - - - - - = - - - - - - - - - - - - - -
................... 3yz ... . . . . . . . . . . ...... 3yz
......... ( 81y^3z - 12xy )
....... - - - - - - - - - - - - - - = 27y^3z^2 - 12xy^2
.................... 3yz
..................... . . . . . . . . . . . . . .. 12xy^2
27y^3z^2 - 12xy^2 = 27y^3z^2 - ----------------
....... . . . . . . . . . . . . . . . . . . . .... {0.0^y^-1}
Negative 1 because yz is being divided into y^3 and z^2.
Hope this makes sense... Next time, try to detail your equasion(s).
--Rob :)
2006-08-21 14:40:10 · answer #1 · answered by stealth_n700ms 4 · 5⤊ 0⤋
Are you studing for your ASVAB? I believe Rob broke it down..you have to do the work in the parentheses forst then do all multiplication and division in left to right order then do additions and subtractions...Remember that only similar or like terms can be combined --terms are similare if they have the same variable, raised to the same power...
2006-08-21 16:35:26 · answer #2 · answered by 69Stang 4 · 1⤊ 0⤋
Proof that Joe is harrassing me because when other people post stuff that has notthing to do with immagration he says nothing but he has to go and talk crap to me every time.... Singling me out for some reason. It's okay cause I'm gonna win him over with my dedication and he will see what a nice girl I am and stop being mean to me for no reason.
2006-08-22 02:29:11 · answer #3 · answered by Anonymous · 0⤊ 1⤋
You asked it so nice that I can't understand why no one will answer your question.
2006-08-21 13:50:33 · answer #4 · answered by Anonymous · 2⤊ 1⤋
Do your own homework honey
2006-08-21 13:47:41 · answer #5 · answered by soulsearcher 5 · 4⤊ 1⤋
Don't tell me what to do! You're not the boss of me! Ask an illegal, I bet he get's it right! LMAO
2006-08-21 13:54:29 · answer #6 · answered by tripledigit 2 · 2⤊ 3⤋
that's what I got, too, dammit
2006-08-21 13:47:50 · answer #7 · answered by john_stolworthy 6 · 3⤊ 1⤋
hahahaha.....they are a litle busy trying to get this thing done.....but we just have to wait for a Japanese, Chinese or Indu guy to take care of this problem...brains in America don't go further that talk trah about MEXICANS.....
2006-08-21 13:48:37 · answer #8 · answered by German R 3 · 0⤊ 6⤋
Come on enlistment date...come on baby...
2006-08-21 14:50:05 · answer #9 · answered by joeandhisguitar 6 · 2⤊ 3⤋
This is what to Immigration ?
2006-08-21 13:52:36 · answer #10 · answered by Zoe 4 · 4⤊ 1⤋