What is the take-off distance required for a boeing 707 at maximum weight?

Answer 1

If you don't mind me using an E-3 (modified 707) as an example then I can give you an answer. Lets use Standard day; 15 deg C, Sea Level, Dry Runway and Pratt & Whittney TF-33 engines, a MTOW of 325,000lbs (max taxi wieght) and no controlling obstacle. IF you had an unlimited length of runway with no slope. Here is the EXACT answer:

6589.98 feet.

Well that is exactly what my Takeoff and Landing Data Program told me.

Answer 2

707 Takeoff

Answer 3

At maximum weight for lift off of a B 707 actually depends on the conditions in which it is lifting off from. Ambient Temperature, Pressure, density Altitude, Take off Configuration, Wind conditions, etc.

Answer 4

Tinkicker, at 130 C, the distance would be zero, because the pilot would be dead and not able to advance the power levers.

Believe Sc0tt; he's got the best answer

Answer 5

I found this "The takeoff field length on a standard day is a relatively long 10 000 feet, which can be directly related to the low thrust loading of 0.23 and the high wing loading of 111.6 pounds per square foot. (See chapter 3 of ref. 176.) " on the following page: http://www.hq.nasa.gov/pao/History/SP-468/ch13-3.htm . I hope this is helpful.

Answer 6

Depends on temperature, humidity, prevailing winds and pressure altitude.

At 130C temp and 100% humidity, with a 90 degree crosswind and the runway at an altitude of 10,000 feet, there is not a runway in the world long enough at MTOW.

Answer 7

Average: 10k ft.

Answer 8

10 miles

Answer 9

At what temp, what altitude and what wind speed????

Answer 10

1000m