The Windmill will power a small fountain. Its design will be of the Dutch type with sails and not blades, it will turm an archamedes screw which will draw water from a sump up to a tank which will be about 9ft from the ground. Gravity will then take the water down a pipe and into the fountain which will be approx. 3 ft. high
2006-08-15 01:29:09 · 7 answers · asked by david c 1 in Environment
Someone said you need the sail 10 feet off the ground. I'll assume that's correct, but I'll correct his mathematics for you:
18ft 6in - 10ft = 8ft 6in radius
diameter=2*radius=2* 8ft 6 in = 17ft.
2006-08-15 01:55:09 · answer #1 · answered by Steve-Bob 4 · 0⤊ 0⤋
As large as you can make them.
If you were to check the real thing you would find that most often the Blades are only a few feet off the ground. So what worked for them should most definetly work for you!!
2006-08-15 01:38:17 · answer #2 · answered by peter gunn 7 · 0⤊ 0⤋
for a modern windmill i belive you are supposed to leave 10 feet between the gound and sails, this leaves you with 8 foot, so 4 foot sails
10 foot for safety..
2006-08-15 01:37:00 · answer #3 · answered by yeah well 5 · 0⤊ 1⤋
You're probably looking at a diameter of 18'
2006-08-15 01:35:23 · answer #4 · answered by Boris 5 · 0⤊ 0⤋
18 ft 5 ins would be cool
2006-08-15 01:35:45 · answer #5 · answered by lykovetos 5 · 0⤊ 0⤋
less than 18.6 else they wont go round very quick
2006-08-15 01:34:38 · answer #6 · answered by Anonymous · 0⤊ 0⤋
ten feet?
2006-08-15 08:04:02 · answer #7 · answered by Conservative 5 · 0⤊ 0⤋