I normally choose a team to watch, depending on how many cute guys they have. This season I'll go by who will play better. So what team will be the team to beat?
2006-08-14 18:43:55 · 16 answers · asked by Tarabeara 4 in Sports ➔ Football (American)
Patriots
Raiders
Eagles
My trifecta to watch
2006-08-14 20:29:28 · answer #1 · answered by Miss. Bliss 5 · 1⤊ 0⤋
The team to beat, because everyone's probably going to want to stomp them into the ground, is the Dallas Cowboys...that's not the same as the team that should be on top...and even as a lifelong Giants fan, I've got to say I like the Colts this year...think the Patriots are just weak enough to be beaten, and I just don't see Pittsburgh repeating...but hey, if I'm gonna dream, let me dream big...how bout Manning v. Manning in the Super Bowl?
2006-08-14 21:47:51 · answer #2 · answered by Anonymous · 1⤊ 1⤋
In the NFC the Seattle Seahawks and the Carolina Panthers. In the AFC the Cincinnati Bengals and Indianapolis Colts
2006-08-14 22:26:28 · answer #3 · answered by Anonymous · 1⤊ 1⤋
The Denver Broncos
2006-08-14 19:46:15 · answer #4 · answered by randy j 4 · 1⤊ 0⤋
Pittsburgh Steelers, Indianapolis Colts, or New England Patriots...
2006-08-14 18:48:07 · answer #5 · answered by misstikal311 4 · 1⤊ 0⤋
New England Patriots
2006-08-14 18:49:26 · answer #6 · answered by I Q 2 · 2⤊ 0⤋
Well technically the team to beat is Pittsburgh as they won last year but Atlanta is the team to watch.
2006-08-14 18:54:56 · answer #7 · answered by Anonymous · 1⤊ 1⤋
The Colts even without edge -best qb,2nd best WR tandem(behind ARI,although with stokley you could argue#1),and pretty good defense
2006-08-14 18:49:08 · answer #8 · answered by Uallsuck 2 · 1⤊ 0⤋
I would say the Colts still. When it comes to the playoffs, that is a different story.
2006-08-14 18:47:13 · answer #9 · answered by Eric R 2 · 1⤊ 1⤋
chargers w/gates,LT,MaCcardel and now rivers wow watch out for the chargers CAUSE THERE GOING TO BE GREAT AND GOING TO WIN 12 GAMES EASILY
2006-08-14 20:27:39 · answer #10 · answered by ? 2 · 1⤊ 1⤋