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okay so it's summer and because it's summer i forget EvErYtHiNg. anyways.....i have a question about ALGEBRA!! There's like a "therom" or a "equation" and it's like has a "4" in it and a "square root sign" in it. I NO THAT IT'S DIVIDED BY 2a.....thats all i no about it. but whats the whole thing?!help!

2006-08-14 16:26:30 · 8 answers · asked by what 2 in Science & Mathematics Mathematics

8 answers

to find the roots of ax^2+bx+c
use the equation:

[-b +/- sqrt(b^2-4ac)]/2a

2006-08-14 16:31:27 · answer #1 · answered by warelphant 2 · 0 0

General Formula for Quadratic Equation

Equation:

ax^2 + bx + c = 0

Roots:

x = [ -b +/- sqrt(b^2 - 4ac)] / 2a

2006-08-15 00:02:37 · answer #2 · answered by ideaquest 7 · 0 0

i would help if it made sense...
do you mean its the square root of 4 divided by 2?
the square root is 2
2 divided by 2 is one...
but if thats not what you meant sorry, i didnt really get it

2006-08-14 23:31:11 · answer #3 · answered by DeAd DiScO 4 · 0 0

It has to be the ones given by Ahab and Warelphant. Its the only basic algebra equation that fits your partial description.

2006-08-14 23:34:13 · answer #4 · answered by iandanielx 3 · 0 0

Quadratic formulat solution to ax^2 + bx + c =0

x = ( b +/- sqrt(b^2 - 4ac) )/(2a)

2006-08-14 23:30:40 · answer #5 · answered by Captain_Ahab_ 3 · 0 0

sqrt(4)/2a = 2/2a = 1/a

2006-08-14 23:30:53 · answer #6 · answered by Anonymous · 0 0

o gosh. im taking algebra 1 this year... i totally forgot!
school starts next week... im so dead!

2006-08-14 23:31:52 · answer #7 · answered by Anonymous · 0 0

yeah. what they said. by the way, it's name is the "quadratic equation". :) geee.

2006-08-14 23:32:54 · answer #8 · answered by angelbymistake 3 · 0 0

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