2006-08-14 15:21:26 · 7 answers · asked by KasuaL 1 in Science & Mathematics ➔ Chemistry
Really depends on the fat and alcohol you are talking about. Alcohol has two ends, hydrophilic end, OH group (water loving) and hydrophobic end (water hating). If the alcohol is long chain molecule with longer hydrophoic end, then probably will be able to dissolve fat better.
2006-08-14 16:56:40 · answer #1 · answered by Mazda5 1 · 0⤊ 3⤋
depends on the type of alcohol. If you have a long chain alcohol molecule that has a majority of hydrophobic carbon, then the chances are high that fat is soluble in alcohol.
2006-08-14 15:26:11 · answer #2 · answered by Natasha B 4 · 1⤊ 0⤋
Think of the general solubility rule as "Like dissolves like" =)
Fat is a non-polar, so by that rule, it would dissolve in a non-polar or one that is close to non-polar alcohol. All alcohols have the OH function group, which gives them polarity, but the length of the molecule would affect its polarity.
Short chain alcohols like ethanol and methanol are pretty polar because they have only one and two carbon atoms in their chain. But as your chain gets longer, the polarity of the molecule becomes less influential, and so fat would dissolve more easily in the alcohol.
2006-08-15 22:46:20 · answer #3 · answered by Anonymous · 1⤊ 0⤋
If you mean ethanol, than no.
But if the alcohol is a long chain alcohol and the fat is a short chain fat, they should be fairly soluble.
2006-08-14 15:27:09 · answer #4 · answered by Andrew L 2 · 0⤊ 1⤋
Fat AKA triglycerides have a hydrophobic hydrocarbon tail and a hydrophillic head. On balance most fats will be insoluble in most alcohols. Micelle formation is likely.
2006-08-14 18:02:18 · answer #5 · answered by d/dx+d/dy+d/dz 6 · 0⤊ 0⤋
If you mean - whether by drinking alcohol u can reduce your fat - No way. u will be adding fat.
2006-08-14 15:45:02 · answer #6 · answered by HMG M 3 · 0⤊ 2⤋
Not according to my gut.
2006-08-14 15:29:56 · answer #7 · answered by Anonymous · 0⤊ 0⤋
not mine no matter how much i try
2006-08-14 15:28:30 · answer #8 · answered by Anonymous · 1⤊ 0⤋