2006-08-14 13:25:48 · 10 answers · asked by ms_jade305 1 in Science & Mathematics ➔ Mathematics
(6+2) squared = 64
square root of (30-5)=5
64/(9-5)-2(25)=64/(4)-50=16-50=-34
you need to do what is in parenthese first. do all your multiplication and division first then add or subtract.
I came up with negative 34
I am reading the problem as the sum of 6 plus 2 divided by the difference of 9 and 5 less 2 times the square root of 30 take away 5
2006-08-14 13:38:07 · answer #1 · answered by T-Jem 3 · 1⤊ 0⤋
1
2006-08-14 20:46:53 · answer #2 · answered by wing14nd 2 · 0⤊ 0⤋
6
2006-08-14 20:32:06 · answer #3 · answered by cramcram62 2 · 0⤊ 0⤋
Not sure if you have parenthesis somewhere --
64 in the numerator divided by 2 is 32.
And then is it times the square root of 30-5 (which would be 5)?
Can you try to type in the question a little bit better?
2006-08-14 20:31:30 · answer #4 · answered by scotsgirl 2 · 0⤊ 0⤋
(6+2)^2/(9-5)-2*sqrt 25 = 8^2/4-2*5= 64/(4)-10 = 64/-6
2006-08-14 20:32:06 · answer #5 · answered by sar 2 · 0⤊ 0⤋
the answer is -10.67and i am sure of it
i cant show solution because its hard to right some symbols
2006-08-14 20:48:00 · answer #6 · answered by Navdeep B 3 · 0⤊ 0⤋
160? I haven done this since school ended.
2006-08-14 20:32:57 · answer #7 · answered by xchrisx9292x 2 · 0⤊ 0⤋
I think you wrote it wrong
2006-08-14 20:31:08 · answer #8 · answered by sweetpea 4 · 0⤊ 0⤋
i
2006-08-14 20:31:30 · answer #9 · answered by infiniti1113 3 · 0⤊ 0⤋
no
2006-08-14 20:29:59 · answer #10 · answered by Anonymous · 0⤊ 0⤋