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geez someone help me. i've been trying to figure this out for way too long.

2006-08-14 10:34:07 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

It would be the decagon..this is a pattern problem

A triangle has 0 diagonals
A quad has 2
A pentagon has 5
A hexagon has 9

You see the numbers go up by 2, then 3, then 4......so by the time you get to decagon, you'll have 35.

There is a formula for this also but sometimes I forget what it is but I can always draw a couple figures to see the pattern again

2006-08-14 10:43:56 · answer #1 · answered by MollyMAM 6 · 0 0

10 (decagon)

Number of diagonals =
(number of sides - 3) * (number of sides) / 2

2006-08-14 17:43:23 · answer #2 · answered by revicamc 4 · 1 0

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