Solve for x ....?

Question

Solve for x :

a^2+b^2x^2+b^2x-a^2x-1=0

Answer 1

a^2 + b^2x^2 + b^2x - a^2x - 1 = 0
b^2x^2 - a^2x + b^2x + a^2 - 1 = 0
(b^2)x^2 + (-a^2 + b^2)x + (a^2 - 1) = 0
(b^2)x^2 + (b^2 - a^2) + (a^2 - 1) = 0

x = (-(b^2 - a^2) ± sqrt((b^2 - a^2)^2 - 4((b^2)(a^2 - 1)))/(2(b^2))

x = (-(b^2 - a^2) ± sqrt(((b^2 - a^2)(b^2 - a^2)) - 4(a^2b^2 - b^2)))/(2b^2)

x = (-(b^2 - a^2) ± sqrt((b^4 - 2a^2b^2 + a^2) - 4a^2b^2 + 4b^2))/(2b^2)

x = (-b^2 + a^2 ± sqrt(b^4 - 2a^2b^2 + a^2 - 4a^2b^2 + 4b^2))/(2b^2)

x = (-b^2 + a^2 ± sqrt(b^4 - 6a^2b^2 + a^2 + 4b^2))/(2b^2)

Answer 2

Rewrite:

(b² + a²)x² + (b² - a²)x -1 = 0

Let r = b² + a²; s = b² - a²

rx² +sx -1=0

x= -s±√[s²+4r]/2r

Now substitute in for r and s.

Answer 3

Quadratic Formula beeotch!!!

Answer 4

a^2-b^2- squareroot of a^4-6b^2a^2+b^4+4b^2 over 2b^2

Answer 5

Hint: Remember, what you do do one side of the equation, you do to the other.

That way, I'm not doing your homework for you.

Answer 6

This isn't a homework site.

Answer 7

Why don't you kids just make up stuff and put it on here?

Answer 8

easy zero

Answer 9

x=x

Answer 10

right, you don't even have to think about that one too hard.....the other side equals zero......