Three guys have to share a room in a hotel. They go to the front desk and are told that the cost is $30. They all give up $10 a piece and go to their room. After a while, the front desk clerk is told that the room should only have been $25. So he gives the bellhop five $1-bills and asks him to return them to the three gentlemen. On his way to the room, the bellhop decides that, rather then trying to split the $5 between the three men, he would give them $1 each and he would keep $2. So, the men all end up paying $9/each for a total of $27 and the bellhop has $2 which adds up to $29. Where is the other dollar? ;-)
2006-08-14 07:33:43 · 31 answers · asked by rapscallion_101 1 in Science & Mathematics ➔ Mathematics
recalculate the math it = $30
2006-08-14 07:37:49 · answer #1 · answered by j@mE$ 6 · 1⤊ 1⤋
You cannot add what one person HAS to what someone else has PAID and come up with any kind of a meaningful number, you have to subtract. Each man has paid $9.
The bellhop has $2.
Men paid: $9 x 3 = $27
$27 - $2 = $25 (that the hotel clerk has)
To look at it from the standpoint of the original $30. Each man has $1.
The bellhop has $2.
The hotel clerk has $25.
$1+$1+$1+$2+25 = $30
2006-08-14 07:40:36 · answer #2 · answered by Anonymous · 2⤊ 0⤋
The actual bill was for $25.
They paid $30.
- - - > The difference was for $5.
- - - > The bellhop returned $3; kept $2
$25 + $3 = $28 + $2 = 30.
The math is works.
2006-08-14 07:41:59 · answer #3 · answered by G_Elisabeth 5 · 1⤊ 0⤋
The problem here is that you shouldn't count the $2 apart from the $27... it's actually a part of the $27 (that $27 that they paid is composed of the $25 which was the fair price they paid for the room and then the $2 which the asshole bellhop kept for himself). The remaining 3 dollars wound up going nowhere because it was paid to the clerk then given back to the guys.
2006-08-14 09:29:56 · answer #4 · answered by Kyrix 6 · 0⤊ 0⤋
3 guys x $10 = $30
oops, mistake, should be $25
3 x $1 bills to the guys, now they've paid $9 each
3 guys x $9 = $27
The bellhop kept $2
$27 - $2 = $25
That's how much the room went for. The math in the question is faulty :)
2006-08-14 08:03:18 · answer #5 · answered by Jesse J 2 · 0⤊ 0⤋
LMAO
You just mixed up your addition and subtraction.
The men paid $10 each and got $1 back. So they now paid $27 not $30 (9x3 = 27).
The room cost $25 and the bellhop kept $2. 25 + 2 = 27.
2006-08-14 07:39:56 · answer #6 · answered by kja63 7 · 1⤊ 0⤋
You don't add the $2 the bellhop kept, you subtract it. The men paid $27 - $2 the bellhop kept = $25 for the hotel.
2006-08-14 07:41:11 · answer #7 · answered by Jim R 2 · 1⤊ 0⤋
The math isn't correct. Each man doesn't pay $9, it would be $8.33. Therefore, the front desk has $25, each man has $1, so that's $3, and the bellhop has $2. $25+$3+$2=$30.
2006-08-14 07:40:23 · answer #8 · answered by Kristine 2 · 0⤊ 1⤋
The cost of the room was $27 minus $2, or $25. The missing $1 comes from adding $27 and $2 and getting the misleading figure of $29.
2006-08-14 07:39:10 · answer #9 · answered by Lulu 2 · 5⤊ 0⤋
1) The hotel front desk keeps $25
2) $1 is returned to each of the three guys making a total of $3 returned.
3) $2 is kept by the bellhop
Add the above three, you get $25 + $3 + $2 viz. $ 30
No missing dollars, eh !!!
2006-08-14 08:03:03 · answer #10 · answered by young_friend 5 · 0⤊ 0⤋
The trick is in how the question is worded. No dollar went missing.
10 + 10 + 10 = 30
9 + 9 + 9 = 27
(10-1) + (10-1) + (10-1) = 27
there are the three dollars given back
the other two...
DAMN YOU YOU JUST BROKE MY HEAD
2006-08-14 07:40:02 · answer #11 · answered by Anonymous · 1⤊ 0⤋