billy is twice as old as sally thier combines age is 28 how old are they?

Answer 1

Ok, two equatinos, two unknowns

Let billy's age be b, and sally's age, s. Then we have

b = 2s, and b + s = 28

Substitute b = 2s into the second equation, and then you have 3s = 28, so s = 9 years, four months. So then billy's age is 18 years, eight months.

Answer 2

Let x be Sally's age

then Billy is aged 2x

The sum of their ages is 28, so:

x+2x = 28

3x=28

x= 28/3 = 9 1/3 = 9.3333333

So Sally is 9 1/3 years, or 9 years 4 months, old

Billy is twice as old, so he must be 18 years and 8 months old.

Checking, 9 years 4 months + 18 yrs 8 months = 27 years and 12 months, or 28 years.

Answer 3

Let us say Sally's age is X. Then billy's age should be twice x i.e 2X.

Combined age is X+2X = 3X = 28. So X = 9 and 1/3

Sally is 9 years 4 months old. Billy is 18 years 8 months old.

Answer 4

Okay.

Let x = Billy's age
Let y = Sally's age

x = 2y
x + y = 28

You know what x equals, so plug it into the second equation.

2y + y = 28
3y = 28
y = 28/3 or
9 and 1/3 yearsor
9 years and 4 months old.

Well, if x = 2y and y = 28/3, then x = 2(28/3)

x = 2(28/3)
x = 56/3
x = 56/3 or
18 and 2/3 years or
18 and 8 months.

Billy is a little over 18 and a half years old.
Sally is almost 9 and a half years old.

Answer 5

billy is 18 2/3 and Sally is 9 1/3

Answer 6

Sally is 9 1/3
Billy is 18 and 2/3

Answer 7

let sally be=x and
so billy will be =2x so the equation is
2x+x=28
3x=28
x=28/3
x=9.33
so the answer is sally is 9 years and 4 months so billy will be
2*(9years and 4 mnths)
so its 18years and 8 months.

Answer 8

Let Billy's age = 2x
Let Sally's age = x
2x + x = 28
3x = 28
x = 9 1/3

Billy's age is 18 2/3 and Sally's age is 9/3.

Answer 9

b = 2s

b + s = 28
2s + s = 28
3s = 28
s = 9 years and 4 months

b = 2(28/3)
b = (56/3)
b = 18 years and 8 months

Billy = 18 yrs and 8 months
Sally = 9 yrs and 4 months

Answer 10

Billy is 18 yrs 8 months old
Sally is 9 years and 4 months old