I have a chemical called Wortmannin that has a Molecular weight of 428.43.?

Question

I need to know how much solvent do I need to add to 1 miligram to make a 1 Molar concentration?

Answer 1

Just a quibble with the prefix of the previous answer:

2.33 x 10 -6 mol / 2.33 x 10 -6 L = 1 M

2.33 x 10 -6 L is 2.33 microliters.

Answer 2

That's 0.00233 mM

(0.001 g/1428.43 g/mol*1000)

You're going to have trouble trying to dilute this, but it'd be: 0.00233 mL, which is 2.33 nanoliters.