can anyone evaulate sin [ tan^-1(-2/3)/2] ?

Answer 1

In both radians and degress the answer is -0.2898
assuming the /2 is after the tan^-1

Answer 2

The Hebrew and Greek words translated "sin" throughout the Bible revolve largely around two major concepts. The first is that of transgression. To transgress means "to step across" or "to go beyond a set boundary or limit." This concept can be compared to an athletic playing field with lines delineating the boundaries within which the game is played. When a player crosses over those boundary lines, he has committed a "transgression" and gone out of bounds. Limits are set that define the playing area, and the players are to stay within the limits of that area.

Most of the other words translated "sin" in the Bible involve a second concept, “to miss the mark.” Again, to use a sports analogy, if a player aims for the goal and misses, how many points does he get? None. He missed the goal, missed the mark at which he was aiming.

This view of sin includes the concept of our going in one direction but straying off course to the side and not continuing in the direction we intended to go, with the result that we don’t reach the goal we intended, We miss.

Read More: http://www.ucgstp.org/lit/gn/gn009/definsin.html

Answer 3

These kind of expressions are best solved by starting from
scratch.

tan^-1(-2/3)/2 is an angle let it be theta.

so make a triangle on a paper of course one angle should be 90.
name a vertice theta.

so opp. to that vertice side length is -2/3
below that side its 2
as tan(theta) = (-2/3)/2

now use pythagorous (height)^2 + base^2= hypotenuse^2

i.e. (-2/3)^2 + (2)^2 = hyp^2
hyp^2= 4/9 + 4
hyp^2 = 40/9
hyp=root(40/9)

so sine(theta) = (-2/3) / (root(40/9))
that is your answer

use a calculator that comes out to be -6.32

hope its helpful

Answer 4

sin [ -2 / 6tan]
= -2sin / 6tan
= -sin.cos / 3sin
= -cos / 3

Answer 5

63.434
I think.
Why?