A.0 B.1 C. 3
2006-08-14 02:22:17 · 5 answers · asked by michelle_keefe 1 in Science & Mathematics ➔ Mathematics
d = b^2 - 4ac
d = (3)^2 - 4(-4)(-28)
d = 9 - 448
d = -439
ANS : A.) 0
2006-08-14 05:56:47 · answer #1 · answered by Sherman81 6 · 0⤊ 0⤋
the given equation may be written as by taking - sign outside
4j^2 -3j +28=0
a=4 ,b=-3, c=28
D^2=b^2 - 4ac
= (-3)^2-4(4)(28)
= 9 -448 wihich is less than Zero therefore does not have any real root or solution
2006-08-14 02:38:30 · answer #2 · answered by Amar Soni 7 · 0⤊ 0⤋
-4j^2 + 3j - 28 discriminant = b^2 - 4ac ..................= 3^2 - 4 * (-4) * (-28) ..................< 0............... no actual roots "every person who won't be able to take care of mathematics isn't totally human. At suited he's a tolerable subhuman who has realized to placed on footwear, bathe, and by no skill make messes in the abode." Robert Heinlein
2016-11-25 00:21:39 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Not this time! We are not here to do your own homework!
2006-08-14 02:29:29 · answer #4 · answered by just "JR" 7 · 0⤊ 0⤋
to what end???? and why????
2006-08-14 02:27:07 · answer #5 · answered by tincre 4 · 0⤊ 0⤋