x^2 + 11x + 121 - x - 96 = 0
x^2 + 10x + 25 = 0
Rho = sqr(b^2 - 4ac) = sqr(100 - 4*1*25) = sqr(100 - 100) = 0
But you should apply the transformation yourself!
2006-08-14 02:26:59
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answer #1
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answered by just "JR" 7
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the discriminant is: b² - 4ac yet formerly we may be able to apply that you may want to convey the equation in the style of Ax² + bx + c = 0, and that's the way you do it: x² + 11x + 121 = x + ninety six x² + 11x - x + 121 - ninety six = 0 x² + 10x + 25 = 0 in the equation a = a million, b = 10 and c = 25 so we are going to use the discriminant to verify the nature of the roots: b² - 4ac (10)² - 4(a million)(25) one hundred - one hundred 0 This shows that the inspiration are actual and equivalent for the above quadratic equation so the expression x² + 10x + 25 is a acceptable sq..
2016-11-25 00:21:28
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answer #2
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answered by ? 4
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x^2+11x+121=x+96
x^2+10x+25=0
discriminant=b^2-4ac here b=10, a=1, c=25.
discriminant=10^2-4*1*25
=100-100
=0
hence ans is
B. 0
2006-08-15 19:50:56
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answer #3
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answered by ankuC2500 1
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B.0
2006-08-14 02:23:42
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answer #4
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answered by arsenal_chun17 3
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The answer is 0. You need to get your equation into Ax+By+C=0 Mode. So subtract your x and 96 from the right to get:
x^2+10x+25
The discriminant is the radical (a.k.a. square root) in the Quadratic Formaula.
Square root of b^2-4ac
Square root of ((10^2)-4(1)(25)
Square root of (100-100) which is of course, 0
2006-08-14 02:38:58
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answer #5
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answered by Anonymous
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First simplify it.
x^2 + 10x + 25 = 0
The discriminant is what is under the radical in the quadratic formula, which is "b^2 - 4ac"
So, it is...
10^2 - 4(1)(25)
100 - 100
0
Answer? B. 0
2006-08-14 07:40:37
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answer #6
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answered by Anonymous
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b
2006-08-14 02:25:16
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answer #7
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answered by ââ¢Â¥ ââ¢Â¥abc 4
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what!
2006-08-14 02:26:35
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answer #8
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answered by Black_ash 3
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