Find the vertex and focus of the parabola ( y+3)^2= 2(x-1)
how to solve this plz tell me in steps so i can understand.
2006-08-12 06:05:56 · 6 answers · asked by Anonymous in Education & Reference ➔ Other - Education
Go and buy a T-93 calculator and type that in. It will solve it for you and show you all the steps.
2006-08-12 06:08:39 · answer #1 · answered by Anonymous · 0⤊ 0⤋
solve for x to obtain the form of the parabola needed to find the vertex and focus.
The form is x = a(y - k) + h
2x - 2 = (y + 3)^2
2x = (y + 3)^2 + 2
x = [((y + 3)^2 + 2] / 2
x = 1/2 (y + 3)^2 + 1
a = 1/2
h = -3
k = 1
The vertex is (h, k) which is (-3, 1)
The focus is (h + 1/4a, k) which is (3 1/2, 1)
2006-08-12 06:29:31 · answer #2 · answered by AskOnlyMe 3 · 0⤊ 0⤋
When you have solved let others also know too.
2006-08-12 06:12:24 · answer #3 · answered by São Ninguém 6 · 0⤊ 0⤋
When you have solved let others also know.
2006-08-12 06:09:34 · answer #4 · answered by lucky s 7 · 0⤊ 0⤋
DO the ( ) first then figure it out. Maybe it will help you A little. That is about all I remember.
2006-08-12 06:13:15 · answer #5 · answered by flutterbye 1 · 0⤊ 0⤋
solve for Y, then graph.. should be come clear
2006-08-12 06:08:46 · answer #6 · answered by tank20760 2 · 0⤊ 0⤋