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2006-08-11 10:32:39 · 5 answers · asked by jrgreenfield1 2 in Science & Mathematics Engineering

5 answers

Level II - 1.1 pounds per square foot
Level III-A - 1.45 pounds per square foot.

The nylon, fasteners, etc, would add to the weights above which are only for the ballastic fiber.

And for more background:

Level II-A (about 16 layers Kevlar 129) stops 9 mm FMJ (Full Metal Jacket) at ~1,090 fps or .357 Magnum JSP (Jacketed Soft Point) at ~1,250 fps

Level II (about 22 layers) stops 9 mm FMJ, at ~1,175 fps or .357 JSP at ~ 1,395 fps

Level III-A, (30 layers) stops 9 mm FMJ at ~1,400 fps or .44 Magnum at ~1,400 fps

Hope that helps.

2006-08-11 10:46:49 · answer #1 · answered by David in Kenai 6 · 1 0

It depends what thickness of Kevlar it was. Grade 29, for instance, which has approximately the tensile strength of glass, has a density of 1.44g/cm2. Multiply that by the thickness of Kevlar you want and you'll have your answer.

Not much!

2006-08-11 10:44:28 · answer #2 · answered by Anonymous · 0 0

It all depends on the weave, this goes from very light under 4oz to as heavy as needed for the application. It can as been weaved or stiched together with carbon fiber and fiberglass

2006-08-12 06:52:12 · answer #3 · answered by David W 2 · 0 0

not much.

2006-08-11 10:37:48 · answer #4 · answered by Harezichi 2 · 0 0

like DUH! it depends on how thick it is

2006-08-11 10:39:49 · answer #5 · answered by Blues Man 2 · 0 0

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