20 steps, assuming Susan walks normal.
2006-08-09 05:41:53
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answer #1
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answered by p_rutherford2003 5
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2) let x characterize the sum of his youngster's a at the same time as now let y characterize Jack's age now In 20 years Jack's age is y + 20, and the sum of his youngster's a at the same time as will be x + 20 + 20 + 20 = x + 60 x = y x + 60 = 5/3(y + 20) x + 60 = 5/3(y + 20) y + 60 = 5/3y + 100/3 y + 60 = a million/3(5y + 100) 3(y + 60) = 5y + 100 3y + 100 and eighty = 5y + 100 100 and eighty = 5y - 3y + 100 100 and eighty - 100 = 2y 80 = 2y 80/2 = y 40 = y Jack is 40 years previous now
2016-11-23 17:46:48
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answer #2
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answered by ? 4
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60 steps for Katie, but only 20 steps for Susan :-)
2006-08-09 05:43:40
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answer #3
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answered by MandyT 2
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twenty paces. susan does not have a crazy tendancy like katie does.
2006-08-09 05:42:30
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answer #4
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answered by Eileen 5
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Assuming a pace = a step, then the answer is 20.
2006-08-09 05:42:00
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answer #5
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answered by kja63 7
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56 steps
she only did the first step and last step 1 time
the other 18 steps, she actually stepped on 3 times
so 18 x 3 = 54
54 + 1 + 1 = 56
2006-08-09 06:02:47
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answer #6
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answered by CR 4
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60 steps (forward and backward) to go 20 forward
2 forward, 1 backward = 1 forward (3 steps total)
2 forward, 1 backward = 2 forward (6 steps total)
etc.
2006-08-09 05:46:52
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answer #7
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answered by Edgar 3
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the problem is with katie not susan. susan will take only twenty paces
2006-08-09 05:41:54
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answer #8
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answered by greatestfan2005 2
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20 steps
2006-08-09 05:45:24
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answer #9
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answered by Anonymous
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susan 20
katie 60
2006-08-09 05:44:49
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answer #10
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answered by jenhockey24 2
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