You roll a number cube 3 times. What is the probability of getting a number greater than 2 all three times?
i need a book or a guideline to solve that and i dont have either of em so..please help...and dont tell me im stupid! thank you!
2006-08-07 14:14:26 · 5 answers · asked by qscwdvrgbn 3 in Education & Reference ➔ Other - Education
dont you have to simplify it? please show the steps....
2006-08-07 14:20:36 · update #1
12:18
2006-08-07 14:17:55 · answer #1 · answered by Abbey 2 · 0⤊ 0⤋
In general probability if very simple. It is the number of ways that the desired outcome can happen divided by the number ways that any outcome can happen.
So in the case of your dice. A dice has 6 sides with numbers from 1 to 6. There are 4 ways that a number greater than 2 can happen ( 3, 4, 5, and 6) and 6 ways that any number can happen. So if you were just rolling the dice once then the probability of a number greater than 2 would be 4 / 6 or 2/3 = 67%
Since 3 rolls are each independent of each other ( that's important) then the probability of all 3 rolls being greater than 2 is
.67 * .67 * .67 or .296 or 29.6%
2006-08-07 21:23:16 · answer #2 · answered by rscanner 6 · 0⤊ 0⤋
12
2006-08-07 21:18:27 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Multiplication rule. For the odds of having multiple mutually exclusive events to all occur, you multiply the odds of each event together.
Your odds of getting a number greater than 2 is 4/6, or 2/3, each time. Your odds of getting it twice are 2/3 x 2/3, which equals 4/9. A third time is 4/9 x 2/3, which is 8/27. Thus, your odds are 8 out of 27. (if you calculate percentage, it's 29.6%)
2006-08-07 21:19:49 · answer #4 · answered by Firstd1mension 5 · 0⤊ 0⤋
6 and 18
2006-08-07 21:45:10 · answer #5 · answered by worm 3 · 0⤊ 0⤋