limiting reagent?

Question

50 kg of N2(g) and 10kg of H2(g) are mixed to produce NH3(g). calculate the amount of NH3 formed.Identify the limiting reagent in the production of NH3in this situation.

it is not a homework problem.For me chemistry is hard.I am not able to understand this sum so I am asking help from you people.

Answer 1

First balance the chemical eqn,
N2 + 3H2 -> 2NH3
That mean u need 3 H2 for every N2
Then find out how many mole of N2 and H2 u have
Then divide the # mole H2 by 3 (cuz of the 1:3 ratio).
Then compare that # with the number of mole of N2 that you have.

Answer 2

A limiting reagent is simply the reactant that runs out first during a reaction. As a reaction proceeds, reactants decrease, while products increase. The limiting reagent is simply the reactant that is used up first. An excess reactant is just any other reactant left over after the limiting reagent is used. There is always a limiting reagent, it just depends on how many moles of what chemical you have.

Answer 3

Calculate the number of mols of each material. Look at the ratio of N to H (1:3). Whichever material runs out first is the limiting reagent.

Answer 4

Sounds like a homework problem which I'm not inclined to do for you. Explain where you are stuck and perhaps someone will help. It does no good for you if someone just gives you the answer. You should be able to figure it out if you read the book or listen to the lectures.

Hint: calculate moles for each reactant and draw the balanced chemical equation.

Answer 5

N2 is the limiting reagent

Answer 6

N2