There are 12 sign of zodiac. How many people would be needed to guarantee that at least six of these people have the same zodiac
2006-08-06 17:06:40 · 12 answers · asked by Anonymous in Education & Reference ➔ Homework Help
please show the formula and working
2006-08-06 18:33:58 · update #1
My answer is (6-1)x12+1=61
means only 61 people would be needed
2006-08-12 15:28:18 · answer #1 · answered by mangaya2 2 · 0⤊ 0⤋
Without a doubt 61 is the correct answer.
If you have 5 people in each of the signs of the zodiac, that would be 60 people. When you get that 61st person, you are guaranteed to have 6 in at least one zodiac.
2006-08-07 01:28:26 · answer #2 · answered by AskOnlyMe 3 · 0⤊ 0⤋
Take 6 and multiply it by 12. That would equal 72. At least 72 are needed to guarentee that at least 6 of these people would have the same zodiac.
2006-08-07 00:11:34 · answer #3 · answered by Anonymous · 0⤊ 0⤋
I don't think there's a correct answer. You need at least six, obviously. 72 might give you even odds. But there's no way to guarantee anything in a truly random event -
2006-08-07 00:15:33 · answer #4 · answered by DashRockwood 3 · 0⤊ 0⤋
72
2006-08-07 00:12:00 · answer #5 · answered by eastcoastraven 5 · 0⤊ 0⤋
Probably 61 :) They don't all need to have 6 people just one of the signs.
2006-08-07 00:11:38 · answer #6 · answered by zara01 4 · 0⤊ 0⤋
law of averages can be used but by looking at it, yeah i agree 72, so randomly your expected value is saying that 6 = 1/12 (k), so k = 72
2006-08-07 01:19:26 · answer #7 · answered by tutor_finance 1 · 0⤊ 0⤋
Infinate
2006-08-07 00:11:24 · answer #8 · answered by robbet03 6 · 0⤊ 0⤋
I think Dash is right. You can have a probability that you will draw six of a certain population. But you can't have a certainty.
2006-08-07 00:17:04 · answer #9 · answered by optionseeker1989 3 · 0⤊ 0⤋
I would think to be sure 72, but I'm sure there's a better answer... I'll think about that haha.
2006-08-07 00:11:35 · answer #10 · answered by j 3 · 0⤊ 0⤋