A mass of clay of volume 432 in.^3 is formed into two cubes. What is the minimum possible total surface are?

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A mass of clay of volume 432 in.^3 is formed into two cubes. What is the minimum possible total surface are?

2006-08-06 13:45:23 · 2 answers · asked by Yogi_Bear_79 3 in Science & Mathematics ➔ Mathematics

Sorry is a two part question. Need to know the Minimum AND the maximum

2006-08-07 13:59:05 · update #1

2 answers

Minimum surface area would obtained as one of the cubes approaches 0x0x0 dimensions. Make one as small as possible and the other one as close as possible to 7.5595262993692389886032636436694 in. cubed.

2006-08-06 13:59:06 · answer #1 · answered by Blues Man 2 · 0⤊ 0⤋

Are the two cubes equal? Because otherwise this question gives an infinitesimal answer. If the two cubes are equal, 432 V/2=216 V for ea cube. Thus, s^3=216 and s=6.
SA=6*6*6=216 per cube.

2006-08-06 21:05:06 · answer #2 · answered by SarcaSTICITSidaS 2 · 0⤊ 0⤋