Can someone help me with solving for an exponent?

Question

I know this is a really simple math problem but I've completely forgotten how to solve for an exponent. The question is
2=1+(.0625/12)^12t. And I need to solve for t. Can someone explain how to go about doing this?

Answer 1

Use logrithms

2 = 1 + (.625/12)^12t

1 = (.625/12)^12t

ln(1) = 12t * ln( .625/12)

well it looks like t is 0 since that is the only exponent that will give you a 1. Also ln(1) = 0

Answer 2

I think you mean:
2=(1+(0.0625/12))^12t.
12t = Log(2)/Log(1+(.0625/12)) = 133.4
t = 11.1