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I'm trying to figure out my average for my class...please help!! I'd also appreciate if you could tell me how you did instead of just the answer, so I know if I'm ever in this situation again.

40% of my grade= 101
30% of my grade= 94
15% of my grade= 80

I have one more paper due, it's 15% of my grade as well....what's the lowest I can get on it and still get an A?

Thanks so much for your help!!!

2006-08-06 10:04:16 · 7 answers · asked by ARoseInBloom 2 in Science & Mathematics Mathematics

7 answers

My solution assumes you need at least 90% for an A. If your teacher's grade scale is different, you'll have to change the 90 below in the equation, though it would be solved the same way:

.4(101) + .3(94) + .15(80) + .15x = 90
40.4 + 28.2 + 12 + .15x = 90
80.6 + .15x = 90
.15x = 9.4
x = 9.4 / .15 = 62 2/3

You'll need a 63 or better to get a 90% A.

2006-08-06 10:17:10 · answer #1 · answered by Anonymous · 6 0

Assuming that an A starts at 90%, the equation you would use is:

(40% of 101) + (30% of 94) + (15% of 80) + (15% of X) = 90,

where X represents your paper score.

(.40*101) + (.30*94) + (.15*80) + (.15*X) = 90

40.4 + 28.2 + 12 + .15X = 90

80.6 + .15X = 90

.15X = 9.4

X = 62.67

So you need at least a 63% (or a D) on the paper to get an A for the course. Unless you really screw up the paper, you're sure to get an A. You go girl!

P.S. If an A does not start at 90, just replace 90 with whatever number is appropriate and solve the same way.

2006-08-06 17:17:31 · answer #2 · answered by Cepheid 3 · 0 0

you would have to get at least a 96 ( assuming you need to get a 95 for the class to get an A)

Calculations:
1) .04 * 101 = 4.04 ( for the 40% of my grade= 101)
2.) .03 * 94 = 2.82 (for the 30% of my grade= 94)
3.) .015 * 80 = 1.2 ( for the 15% of my grade= 80)

you add these up 4.04 + 2.82 + 1.2 = 8.06

that means at this point you have a 80.6 ( your just move the decmal over one place)

to get a 95 ( i think thats what you need for and A) you subtract 8.06 - 9.5 = 1.44
so you find x in this equation .015 * x = 1.44 ( like how i did it above for the first three grades)
so, 1.44/ .015 = 96

feel free to email me if you have any questions

2006-08-06 17:21:44 · answer #3 · answered by liss843 4 · 0 0

depends on how well your classmates do.

your weighted average score is
0.4*101 + 0.3*94 + 0.15*80 + 0.15*

and that weighted average has to be in top 33% of the class to get an A (assuming the curve means equal number of A's, B's and C's), or some other cutoff.

and that "33% of the class" depends on how well everybody else does.

so get off Y!Answers and try to do your best on that paper.

2006-08-06 17:14:43 · answer #4 · answered by Anonymous · 0 0

What is minimum you need for an "A" - 90? 95?

For this, assume 90 is what you need.
solve for X - your last paper.
(0.40 x 101) + (0.30 x 94) + (0.15 x 80) + (0.15 x X) = 90
Doing the math:
40.4 + 28.2 + 12.0 +.15X = 90
80.6 + .15X = 90
Subtract 80.6 form both sides:
.15X = 9.4
Divide both sides by 0.15:
X = 62.6 (approx) - say 63.

So if 90 is an "A", you need 63 on your last paper.

2006-08-06 17:18:10 · answer #5 · answered by dollhaus 7 · 0 0

let assume your A grade is 90 then
(0.4 x 101) + (0.3 x 94) + (0.15 x 80) + (0.15 x paper grade) = 90
40.4 + 28.2 + 12 + 0.15 x paper grade = 90
80.6 + 0.15 x paper grade = 90
0.15 x paper grade = 90 - 80.6 = 9.4
paper grade = 9.4 / 0.15 = 62.7

so in order to get A you must get 62.7 grade on your paper

2006-08-07 04:25:53 · answer #6 · answered by Anonymous · 0 0

It's broken down into 100% so...

101(0.40) + 94(0.30) + 80(0.15) + ??(0.15) = ...

Just substitute your final score...or insert 0 for the ?? to determine the lowest score you can get.

2006-08-06 17:19:23 · answer #7 · answered by Kurt 3 · 0 0

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