Find the time required for an object to fall from 1400 ft. High. Use this formula?

Question

t=1/4 (radical sign w/ an s under it)

Answer 1

It'll be like:

t = ¼√s
t = ¼√1400
t = 9.35 time units, i guess its seconds.

If you want to know why they used that formula, i'll give you a further explanation, i hope i win these 10 points AND you learn to deduce your own expressions:

The cimematics movement equation is:

s - s' = v' × t + ½ × a × t²

Where the symbols with (') are the ones of initial conditions.
Now, let's see: s' and v' are zero. So we get:

s = ½at²
t = √(2s/g)

Now,
a = g = -32.2(ft²/s)
t = √(2×s/32.2) = √(s/16.1) = √[(1/16.1)(s)]

They obviously rounded it to 16, operated the square root, and it goes like it was in the problem:

t = ¼√s

Answer 2

Change 1400 ft to meters and use
height = (1/2) x (9.8 m/s2) x t^2
Then you find t in seconds.
Th

Answer 3

(1 / 4) * sqrt(1 400) = 9.35414347 is s is height (acc. to your formula)

Answer 4

formula is
time = sqrt(2*distance/9.8)

where sqrt is square root
distance is in meters (feet*0.3)

and time will be in seconds.

if you can't figure it out from here, you deserve your F.