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The balanced equation is 2KCLO3 + 2KCL + 3O2

Please explain how to set up for answer

2006-08-06 04:33:30 · 4 answers · asked by Emily F 1 in Science & Mathematics Chemistry

4 answers

The first thing to do is to convert from grams to moles, since 'masses' don't tell you anything about the number of particles interacting with each other (different particles weigh different amounts).

1 mole of KClO3 has one mole of K (39.10 g), one mole of Cl (35.45 g), and three moles of oxygen (3 x 16.00 g, or 48.00 g). The total molar weight for KClO3 is (39.10 g + 35.45 g + 48.00 g) = 122.55 g.

So if one mole of KClO3 weighs 122.55 g, then what fraction of a mole is 5 g? Divide 5 g by 122.55 g, and you'll find that you have 0.0408 moles of KClO3. That's the number of particles of the substance you have.

For every 2 particles of KClO3 that react, you get 3 particles of O2 at the end. Multiply the number of particles of KClO3 (0.0408 mol) by 3/2 to get the final number of particles of O2: 0.0612 moles.

Almost done. Now we know the number of *particles* of O2 at the end, but we need to convert back to volume. Since one mole of a gas, at STP, always takes up 22.4 liters, we need to figure out how much space 0.0612 moles take up. Just multiply this fraction of a mole by the space taken up by one mole (0.0612 mol x 22.4 L/mol) to get your final answer: 1.37 L.

2006-08-06 05:03:22 · answer #1 · answered by Thomas C 2 · 3 0

First Step: Calculate how many moles are in 5g of KClO3.

No. of moles = Mass/Mass of 1 mole
= 5g / 122.5
= 0.04 mole KClO3

Second Step: Use the equation

According to the equation, in theory every 2 moles of KClO3 will produce 3 moles of O2. However, as we calculated above only 0.04 moles of KClO3 are being used so u need to calc. how much O2 is produced from that amount of KClO3. So u say...

2 moles KClO3 produces 3 moles of O2
therefore 0.04 moles KClO3 will produce 3/2 x 0.04 mole O2
=0.06 mole O2

Third Step: Calculate the volume of gas produced by 0.06 moles of O2.

Volume of Gas= No. mole x stp (22.4dm3)
= 0.06 mol x 22.4 dm3mol-1
= 1.37 dm3 or L O2

I hope this detail will help u.

2006-08-06 05:12:57 · answer #2 · answered by xtra-great-gal 2 · 0 0

Molar mass of KClO3 = 39+35.5+3x16 g = 39+35.5+48 g = 122.5g

2x122.5g releases 3x22.4 l of O2

So, 5g releases 1.37 l of O2

2006-08-06 04:42:55 · answer #3 · answered by ag_iitkgp 7 · 0 0

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2006-08-06 04:49:57 · answer #4 · answered by notdon 1 · 0 0

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