The Balanced equation is N2+3H2=2NH3
Please explain how to get the answer.
2006-08-06 04:10:00 · 2 answers · asked by Emily F 1 in Science & Mathematics ➔ Chemistry
28gms of N2 molecule occupies around 22 Litres at STP. After reacting with Hydrogen it shall weigh 34 gms. Two moles of ammonia are formed from each mole of nitrogen.
34 gms of ammonia is formed from 28 gms of N2
(25/28)*34 gms of ammonia are formed from 25 gms of N2
34 gms of ammonia occupies 44 Ltrs
(25/28)34 gms shall occupy (25/28)(34/34)*44
Hence it shall occupy 2*(25/28)*22 Litres or 44X25/28 litres of ammonia. which is 39.29 Litres.
2006-08-06 04:30:32 · answer #1 · answered by krishash49 2 · 1⤊ 0⤋
Molar mass of N2 = 28
So, 28g produces 2x22.4l = 44.8l
So, 25g gives = 44.8x25/28 l = 40l of NH3
2006-08-06 11:22:26 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋