Reactivity difference between Iodine and flourine?

Question

Iodine is a solid and the prence of 'd' orbital screens the valence electron less effitively, then the value of I.E and bond enthalpy are less than F. But is less reactive than F. Why

Answer 1

Fluorine is the most active nonmetal because it is most anxious to gain an electron and fill its outer ring to become F-. All the halogens under F are less active in order, with Iodine the least active of the halogens. At of course excepted, but there isn't any to test.

On the other end of the Periodic table, Francium is the most active metal because it is the metal most anxious to give away that 1 outer electron. to become Fr+

Answer 2

Metals become more reactive when their outer electrons are farther away or shielded from the nucleus, because a metal's goal is to lose electrons. Nonmetals, on the other hand, are electronegative--they have a 'pull' for electrons--and they want to gain one or more electrons.

Fluorine is more reactive than iodine because there is less space between the nucleus and the valence shell. That means that the fluorine nucleus is pulling harder on those outside electrons, and that the possibility of the atom gaining another electron is higher. With nonmetals, therefore, the higher up you are in the group, the more reactive the element.

Answer 3

The ionization energy is the energy necessary to remove an electron from a neutral atom. Due to the fact that the iodine atom is the larger atom and that its outer electrons are less attracted by nucleus, then it is easier (it takes less energy) for the Iodine atom to lose an electron than for the fluorine atom to do so. That's why I has a lower I.E than F.

However, because both Iodine and Fluorine are non-metals they prefer to gain electrons rather than lose electrons. Since F is much smaller than I then it is easier for F to gain another electron than it is for Iodine to do so. That is why Fluorine is more reactive than Iodine.

Answer 4

Its EA which plays the major role.