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I will use the building as one side of the yard.
What is the minimum amount of fencing that must be used to enclose the remaining 3 sides of the yard.

2006-08-06 02:23:05 · 6 answers · asked by tjhauck2001 2 in Science & Mathematics Mathematics

6 answers

You didn't mention the size of the building, but I'll assume that the side you want the yard on is over 140 feet in length.

The minimum perimeter using straight lines is a square, and the square root of 20,000 sq. ft. is 141.42 ft.

With the building making up one side of the square, you'll need 3 * 141.42, or 424.26 ft. or rounding up, 425 feet.

2006-08-06 03:06:22 · answer #1 · answered by Jay S 5 · 0 0

Area formula for a rectangle is:

A = L x W

20000 square feet

20000 = 100 x 200

There was no mention on which side the building will be located.

Assumption: The building is 100 feet long

The amount of fenceing is 500 feet

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Asumption: The building is 200 feet long

The amount of fencing is 400 feet

The minimum amount of fencing required is 400 feet

The answer is 400 feet

2006-08-06 12:23:46 · answer #2 · answered by SAMUEL D 7 · 0 0

400 feet. Usuming the building is 200' wide, 20000 sqft can be done (assuming 4 total corners of 90 degrees each) with the short sides being 0.5 times the building width..

So the enclosed ractangle would 200' by 100' or 20000 sqft and that can be with 400 feet of fence.

Now, consider this... How about enclosing 20000 sqft of area with a flexible fence having no corners attached 200' apart to points of the building. The shape would be the same as the shape of a suspended rope attached at the ends 200' apart (I think?). It would be somewhat elliptical looking or like that of a suspension bridge.

How long would that curvable fence be and what's the best shape to maximize the area inside the fence?

That is a solvable equation, but I'd have to dig out my college math books to figure the length of the rope needs to encompass 20000 sqft.

2006-08-06 16:34:57 · answer #3 · answered by Blues Man 2 · 0 0

400 feet

A 200*100 ft storage area provides the required space while using the least amount of fence. Make one of the long edges of the storage yard (200 ft) the wall of the building.

2006-08-06 12:46:49 · answer #4 · answered by jimbob 6 · 0 0

the minimum amount of fencing around a rectangular yard is when the rectangular yard is a square.
In that case one side of the square is sqrt(20,000) thus you will need 3 times sqrt(20,000) fences.
( i thought i answered this question before ..... )

2006-08-06 10:39:31 · answer #5 · answered by gjmb1960 7 · 0 0

a rectangle is defined as a parallelogram which has 4 right angles. Therefore to use the least amount of fence use as much of the building as possible for one side.

2006-08-06 09:37:31 · answer #6 · answered by Michael B 1 · 0 0

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