1) A boy was sent to buy a rupee worth of oranges. He ate 5 & in consequence his master had to pay at the rate of 20 paise per dozen more than the market price. How many oranges did the boy buy?
2006-08-06 02:15:07 · 9 answers · asked by Malfoy vs Potter 5 in Science & Mathematics ➔ Mathematics
Let the cost of one dozen oranges be x.
Therefore, one orange is x/12
Now if the boy ate 5 oranges, the cost of one dozen oranges become (x + 0.2) rupees. Therefore, one orange is (x + 0.2)/12
Let the number originally bought be y. Therefore, after the boy has eaten 5, the number of oranges become (y - 5)
Therefore,
(x/12) * y = (y - 5) * (x + 0.2)/12
or, xy = (y - 5) (x + 0.2)
or, xy = xy + 0.2y - 5x - 1
or, 0 = 0.2y - 5x - 1
or, 2y = 50x + 10
or, y = 25x + 5 --------- equation 1
as the master pay 1 rupees, the number of oranges originally bought were 1/x/12 = 12/x
Therefore, y = 12/x -------------equation 2
From Equation 1 and 2,
12/x = 25x + 5
or, 12 = 25x^2 + 5x
or, 25x^2 + 5x - 12 = 0
or, 25x^2 + 20x - 15x - 12 = 0
or, 5x (5x + 4) - 3 (5x + 4) = 0
or (5x - 3) (5x + 4) = 0
or, x = 3/5 or -4/5
as the cost can not be negative, x = 3/5
From equation 2, y= 12/3/5 = 20 oranges
The boy bought 20 oranges
2006-08-06 05:05:45 · answer #1 · answered by Iluvharrypotter_tonima 2 · 0⤊ 0⤋
5
2006-08-06 09:19:29 · answer #2 · answered by Eric W 3 · 0⤊ 0⤋
5
2006-08-06 09:18:02 · answer #3 · answered by jewingengleman 4 · 0⤊ 0⤋
5.
2006-08-06 10:24:40 · answer #4 · answered by Kenneth Koh 5 · 0⤊ 0⤋
the 5 he ate
2006-08-06 09:21:01 · answer #5 · answered by sswan007 3 · 0⤊ 0⤋
55 years
2006-08-06 09:18:19 · answer #6 · answered by Anonymous · 0⤊ 0⤋
7 or 5 maybe. d question aint complete.
2006-08-06 10:53:29 · answer #7 · answered by funmzire 5 · 0⤊ 0⤋
Homework huh? What a drag.
2006-08-06 09:17:22 · answer #8 · answered by iloveicecream103 3 · 0⤊ 0⤋
Do it ur self
2006-08-06 09:25:30 · answer #9 · answered by Cool Chap 1 · 0⤊ 0⤋