pls help me!!! algebra problem?

0 ⤊

pls help me!!! algebra problem?

2x(x-1)^2(x-4)/x-7 less than or equal to 0

2006-08-06 01:25:40 · 4 answers · asked by Romualdo,Jr. L 1 in Science & Mathematics ➔ Mathematics

4 answers

2x(x-1)^2(x-4)/x-7 =<0
I guess it should be
{2x(x-1)^2}(x-4)/(x-7) =<0
x cannot be 7

-----0+++++++++++++ x
-------1++++++++++++ x-1
-------1++++++++++++ x-1
--------------4++++++++ x-4
-----------------------7+++ x-7
-----0+1++4-------7+++ 2x(x-1)^2(x-4)/(x-7)
{2x(x-1)^2}(x-4)/(x-7) =<0 if
x=<0 or 4= Th

2006-08-06 02:20:45 · answer #1 · answered by Thermo 6 · 0⤊ 0⤋

x=4 and 1

2006-08-06 03:31:49 · answer #2 · answered by Kenneth Koh 5 · 0⤊ 0⤋

x=4 and x=1

2006-08-06 01:45:50 · answer #3 · answered by brightstar 2 · 0⤊ 0⤋

x1= -4

x2=0

x3=1 (the curve bounces off of that critical point)

7 is an asymptote

2006-08-06 01:59:57 · answer #4 · answered by womfalcs7 2 · 0⤊ 0⤋