i want to buy 10 super bright LEDs and set them up with a 12v pwr DC in Parellel. How do i order the lights and resistor.????
2006-08-04 14:55:08 · 13 answers · asked by BigRey 2 in Consumer Electronics ➔ Other - Electronics
How many lights are you connecting and are they in sequence or parallel? For a single mild at 20 mA, 9.Three V, you need a 305 Ω , 1/8 watt, resistor, although 1/4 watt bwould be higher as 1/eight is walking almost its restrict. For 2 or more lights in parallel, each must have its own resistor as above. For two or more lights in series, multiply the 3.2 volts by means of the number of lights to get the whole voltage, then subtract the complete from 9.Three volts to get the voltage drop. Divide this via 20 mA (zero.02 A) to get the resistance multiply the voltage drop through 20 mA (0.02 A) to get the vigor dissipation of the resistor.
2016-08-09 10:19:17 · answer #1 · answered by matzen 4 · 0⤊ 0⤋
How many lighting fixtures are you connecting and are they in sequence or parallel? For a unmarried mild at 20 mA, nine.three V, you want a 305 Ω , a million/eight watt, resistor, even though a million/four watt bwould be bigger as a million/eight is strolling almost its prohibit. For 2 or extra lighting fixtures in parallel, every must have its possess resistor as above. For 2 or extra lighting fixtures in sequence, multiply the three.two volts through the quantity of lighting fixtures to get the complete voltage, then subtract the complete from nine.three volts to get the voltage drop. Divide this through 20 mA (zero.02 A) to get the resistance multiply the voltage drop through 20 mA (zero.02 A) to get the vigour dissipation of the resistor.
2016-08-20 23:45:10 · answer #2 · answered by shannonhouse 3 · 0⤊ 0⤋
how many lighting are you connecting and are they in sequence or parallel? For a single easy at 20 mA, 9.3 V, you want a 305 ? , a million/8 watt, resistor, even inspite of the incontrovertible fact that a million/4 watt bwould be extra useful as a million/8 is working on the threshold of its decrease. for 2 or extra lighting in parallel, each and each could desire to have its very own resistor as above. for 2 or extra lighting in sequence, multiply the three.2 volts by ability of the type of lighting to get the excellent voltage, then subtract the excellent from 9.3 volts to get the voltage drop. Divide this by ability of 20 mA (0.02 A) to get the resistance multiply the voltage drop by ability of 20 mA (0.02 A) to get the potential dissipation of the resistor.
2016-11-03 22:11:42 · answer #3 · answered by harib 4 · 0⤊ 0⤋
Radio Shack
2006-08-04 14:58:12 · answer #4 · answered by UNITool 6 · 0⤊ 0⤋
Go to Radio Shack, They have a very large assortment of light emitting diodes and resistors. They have many different voltage LEDs so you shouldn't need resistors,unless you just couldn't resist......
2006-08-04 15:00:45 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Radio Spares, Maplin
2006-08-04 14:57:15 · answer #6 · answered by Joquius 2 · 0⤊ 0⤋
Electrosonic Allied Electronics etc
2006-08-04 14:59:09 · answer #7 · answered by leafsfan1000 3 · 0⤊ 0⤋
Radio Shack store or on-line
2006-08-04 14:59:08 · answer #8 · answered by DrB 7 · 0⤊ 0⤋
Edmund Scientific, I think. Careful, though, even the little $3 jobs in the store can blind you. LED's not lasers. Really.
2006-08-04 14:59:08 · answer #9 · answered by gabluesmanxlt 5 · 0⤊ 0⤋
Maybe just drop into Radio Shack or something...
2006-08-04 14:58:38 · answer #10 · answered by snvffy 7 · 0⤊ 0⤋