2006-08-03 18:47:03 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Engineering
consider the percentage output. say 1st one give u 80%, then 2nd one give u another 80% of the remaining... so u get higher yield instead of one. a bigger CSTR dun give that. and bigger usually means lower percent, due to the temperature pressure control and extend of reaction etc.
2006-08-03 18:54:02 · answer #1 · answered by Ant 2 · 0⤊ 0⤋
Two CSTR's in series adds residence time to the reaction. As long as sufficient reactants remain and the chemistry is not reversible, you will get more conversion. However, it doesn't necessarily mean anything in regard to yield.
2006-08-04 13:36:28 · answer #2 · answered by richard Alvarado 4 · 0⤊ 0⤋
CSTRs in series:
X=1-1/((1+Da)^n)
CSTRs in paralled:
X=((1+2Da)-sqrt(1+4Da))/(2Da)
where Da=-rAo V/ FAo
2006-08-04 01:55:31 · answer #3 · answered by bbqsunflowerseeds 2 · 0⤊ 0⤋