Less than 25%. It's only 25% if you pick out one card.
2006-08-02 12:41:46
·
answer #1
·
answered by Anonymous
·
0⤊
0⤋
In the experiment of drawing two card from a pack of 52 cards,
Total Number of Possible Choices
= Number of ways in which two cards can be drawn from the total 52
â n= 52C2
â n= (52 x 51) / 2
â n = 1326
Let "A" be the events of the two cards drawn being are clubs
For Event "A"
-------------------
For Favourable choices
[Clubs(â£)] Others Total
Available 13 48 52
To Choose 2 0 2
Choices 13C2 48C0 52C2
Number of Favourable/Favorable Choices
= The number of ways in which Two clubs can be drawn from the total 13
â m = 13C2
â m = (13 x 12) / 2
â m = 13 x 6
â m = 78
Probability of the cards drawn being are clubs
â Probability of occurance of Event "A"
= (Numer of Favourable/Favorable Choices for the Event 'A') / (Total Number of Possible Choices for the Experiment)
â P(A) = m / n
â P(A) = 78 / 1326
â P(A) = 1 / 17
â P(A) = 0.058823
For more detailes and better understanding and dynamic thinking:
http://www.futureaccountant.com/probability/
http://www.schoolingkids.com/probability/
2006-08-03 23:27:00
·
answer #2
·
answered by Supporter 2
·
0⤊
0⤋
one in eight tries considering that clubs equal 1/4th of the cards.
The odds of drawing two clubs in a row from a full deck is 8-1.
2006-08-02 19:43:41
·
answer #3
·
answered by Murph 3
·
0⤊
0⤋
5.9%
How do you get this?
The chance of pulling one club is 13/52, or 25%.
The chance of pulling a second club AFTER you already pulled one is 12/51, or 23.5%.
The chance of pulling two clubs one after the other is .25 x .235, or 5.9%. You have to multiply the probabilities together. Why? Because the chance of pulling two clubs is less than the chance of pulling just one club.
2006-08-02 20:25:07
·
answer #4
·
answered by Crazy Eagle 3
·
0⤊
0⤋
25%
2006-08-02 19:40:23
·
answer #5
·
answered by Anonymous
·
0⤊
0⤋
100% is the cards are face up and you choose them.
2006-08-02 19:42:29
·
answer #6
·
answered by Meow 3
·
0⤊
0⤋