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6 answers

Less than 25%. It's only 25% if you pick out one card.

2006-08-02 12:41:46 · answer #1 · answered by Anonymous · 0 0

In the experiment of drawing two card from a pack of 52 cards,

Total Number of Possible Choices

= Number of ways in which two cards can be drawn from the total 52
⇒ n= 52C2
⇒ n= (52 x 51) / 2
⇒ n = 1326

Let "A" be the events of the two cards drawn being are clubs

For Event "A"
-------------------
For Favourable choices

[Clubs(♣)] Others Total
Available 13 48 52
To Choose 2 0 2
Choices 13C2 48C0 52C2

Number of Favourable/Favorable Choices

= The number of ways in which Two clubs can be drawn from the total 13

⇒ m = 13C2
⇒ m = (13 x 12) / 2
⇒ m = 13 x 6
⇒ m = 78

Probability of the cards drawn being are clubs
⇒ Probability of occurance of Event "A"
= (Numer of Favourable/Favorable Choices for the Event 'A') / (Total Number of Possible Choices for the Experiment)
⇒ P(A) = m / n
⇒ P(A) = 78 / 1326
⇒ P(A) = 1 / 17
⇒ P(A) = 0.058823


For more detailes and better understanding and dynamic thinking:

http://www.futureaccountant.com/probability/

http://www.schoolingkids.com/probability/

2006-08-03 23:27:00 · answer #2 · answered by Supporter 2 · 0 0

one in eight tries considering that clubs equal 1/4th of the cards.
The odds of drawing two clubs in a row from a full deck is 8-1.

2006-08-02 19:43:41 · answer #3 · answered by Murph 3 · 0 0

5.9%

How do you get this?

The chance of pulling one club is 13/52, or 25%.

The chance of pulling a second club AFTER you already pulled one is 12/51, or 23.5%.

The chance of pulling two clubs one after the other is .25 x .235, or 5.9%. You have to multiply the probabilities together. Why? Because the chance of pulling two clubs is less than the chance of pulling just one club.

2006-08-02 20:25:07 · answer #4 · answered by Crazy Eagle 3 · 0 0

25%

2006-08-02 19:40:23 · answer #5 · answered by Anonymous · 0 0

100% is the cards are face up and you choose them.

2006-08-02 19:42:29 · answer #6 · answered by Meow 3 · 0 0

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