tell me effect on motor & capacitor in details& give me names of books to study the effect of leading power factor on motor ,capacitor& supply system
2006-08-01 23:08:23 · 6 answers · asked by manggessh p mane 1 in Science & Mathematics ➔ Engineering
if the motor runs at no load, it will just spin at its maximum speed. if you over correct for the power factor, then the overall pf for the morot circuit will be leading somewhat. it's nothing to worry about unless you push more amps through the motor than it's made for.
2006-08-01 23:21:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Think of Induction Motor as an Inductor and If you add a Capacitor to the circuit, it's an LC circuit.
Many aspects to look at a LC circuit, but in this case, what we should look at for this application is the amount of L and C. If more C, you will get leading PF. If more L, you will get lagging PF.
Do not see any effect on the L and the C. More for the supply system, as the meter from the utility is reading only the KW, so they requires you to have best unity PF.
Agreed with previous post that it all boils down to the current drawn by the circuit which could be potentially dangerous if you hae the exteme of either L and C, where the KW might be small be the current drawn is higher than norm.
2006-08-02 15:26:27 · answer #2 · answered by knight0198 1 · 0⤊ 0⤋
a three area motor can't run on organic unmarried area ability. Capacitors could properly be utilized to derive the area delay had to make one of those motor run, yet its performance will commonly be impaired. An induction motor won't be able for use as a generator because there is no longer something to generate the sphere magnetism; you want a synchronous motor or different style of motor with a generated (or everlasting magnet) field to act as a generator.
2016-11-27 20:22:56 · answer #3 · answered by minissale 4 · 0⤊ 0⤋
You are dicing with DEATH by correcting the PF to unity when the motor is at no load........
Most unloaded squirrel cage motors exhibit a PF of around .3 lag as soon as the load increases the PF moves towards unity (1) so that at full load it will be around .8 or better.
So if you correct the PF at no load to unity the PF will be .7 or .8 leading at full load...... this means that the cables/winding etc. will be subjected to high voltages causing flash overs/shorts etc.
It may also cause Ferro Resonance in the transformre etc.....
Source: Electrical Engineer with 40+ years experience
2006-08-02 04:12:05 · answer #4 · answered by Bazza66 3 · 0⤊ 0⤋
The idea of pf correction is to reduce costs, the closer you get to unity, the cheaper the electricity usage costs. So it does not matter if you over correct the pf when a motor comes off-load, you will just pay a bit more for the privelege
2006-08-02 00:01:30 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Easy - it will probably be the end of the motor as you know it!
2006-08-01 23:14:04 · answer #6 · answered by Anonymous · 0⤊ 0⤋