two coinsare tossed together.thae probability of getting two heads is?

Question

A. 1/2
B.1/4
C.1/8
D.1/3

Answer 1

honestly, the correct answer in this particular case is 1/3. Here's the reason:

Since you are tossing them at the same time, there are only three possible outcomes: H-H, T-H OR H-T, and T-T. You can't distinguish between the two middle outcomes because the two coins are tossed together. IF they were tossed separately, there would be four possible outcomes, the middle two being separate events, but BECAUSE they are tossed together, the middle two outcomes are only one event.

Answer 2

1 in 4

Answer 3

1/2

Answer 4

B 1 in 4

The 4 possibilities are:
T + T
H + T
T + H
and finally H + H

Answer 5

In the experiment of tossing a two coins,

Total Number of Possible Choices = 4 {(T,T) (T,H) (H,T) (H,H)} ⇒ n = 4

Let "A" be the event of getting two heads on throwing the coin.

For Event "A"
------------------

Number of Favourable/Favorable Choices = 1 {(H,H)} ⇒ m = 1

∴ Probability of getting two heads on throwing the coin.

⇒ Probability of occurance of Event "A" = (No. of Favourable/Favorable Choices for the Event) / (Total No. of Possible Choices for the Experiment)
⇒ P(A) = m / n
⇒ P(A) = 1 / 4

For moredetailes and better understanding:

http://www.futureaccountant.com/probability/problems-solutions/

http://www.schoolingkids.com/probability/

Answer 6

considering that 2 money are tossed rapidly, the pattern area for the shape i.e, each and each and every of the situations that are conceivable are as follows: {HH, HT, TH, TT} the position H refers to flow and T refers to tail through the undeniable fact that is precisely one head, the situations that are useful are HT and TH to that end 2 situations out of four are useful i.e danger = 2/4 = a million/2

Answer 7

the ans is 1/2

Answer 8

B

Answer 9

B