When you divide 7 by 5, you get an answer of 1 with a remainder of 2 (1 R 2). When you divide 9 by 7, you get 1 R 2. Since the answers are the same for the two problems, the transitive property of equality would allow us to say that seven divided by 5 is equivalent to 9 divided by 7. We know that is not true because one gives a decimal answer of 1.4 and the other gives a decimal answer of 1.285714 . What is wrong?
2006-07-31 07:33:49 · 4 answers · asked by ras 1 in Education & Reference ➔ Home Schooling
Because 1 R2 is not a number. It is the output of an algorithm. As such it is incorrect to say that 7/5 = 1R2, because one is a number and the other is not. If you wanted to actually convert this to a number, you have to actually divide the remainder by the divisor and add it to the whole number quotient. Thus, 7/5=1+2/5 and 9/7=1+2/7. But note that 2/5 != 2/7, so you shouldn't expect the two numbers to be the same.
2006-07-31 15:10:56 · answer #1 · answered by Pascal 7 · 0⤊ 0⤋
Transtitive property doesn't work on quotient remainders.
2006-07-31 07:35:29 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Answer. 1R2 is a geminii.
2006-07-31 08:11:53 · answer #3 · answered by Anonymous · 0⤊ 0⤋
It goes a=b, b=c, so a = c. That's why.
2006-07-31 09:30:31 · answer #4 · answered by anon200808 1 · 0⤊ 0⤋