2006-07-25 10:53:07 · 10 answers · asked by DL 6 in Health ➔ Mental Health
Yes! http://groups.yahoo.com/group/AnswerholicsAnonymous/
2006-07-26 08:14:09 · answer #1 · answered by Blue 7 · 4⤊ 2⤋
Ask Question
Answer Question
Answer Question
Answer Question
Answer Question
Answer Question
Choose A Best Answer
Rate An Answer
Answer Question
Answer Question
Answer Question
Repeat Process
2006-07-25 17:59:06 · answer #2 · answered by Shaula 7 · 0⤊ 0⤋
My computer broke for a week and after it was fixed, I find that I spend less than 10 minutes a day here. The points are worthless and the people don't listen to good advise and they don't vote for the best answer.
Once I realized what this place is about, I only give answers to good question and people, who I think will take advise.
Now I'm wonder why I answered your question. :-) hehe
2006-07-25 17:59:03 · answer #3 · answered by my_alias_id 6 · 0⤊ 0⤋
Do you really want one?! Does anybody? It IS very addicting but SO interesting. Sometimes I feel guilty for being at it so much of the time but right now with school out I have more free time.
2006-07-25 17:59:56 · answer #4 · answered by Goldenrain 6 · 0⤊ 0⤋
I don't think so. Why don't you start one? You could use Geocities for your home page and then start a 12 step forum on yahoo forums or groups. Then you could have live chat conferences. Just like real meetings!
2006-07-25 17:58:06 · answer #5 · answered by sparkles 4 · 0⤊ 0⤋
Answer 12 questions and sign off!
2006-07-25 18:34:44 · answer #6 · answered by Anonymous · 0⤊ 0⤋
FINALLY! What seems to be an original question.
Uh.... I don't think there is.
I know of an effective one step program though -- have your internet disconnected.
2006-07-25 17:59:12 · answer #7 · answered by Blah Blah Blah 3 · 0⤊ 0⤋
Join Answerholics Anonymous :-)
2006-07-25 18:03:41 · answer #8 · answered by Anonymous · 0⤊ 0⤋
It's in the development stage
2006-07-25 17:56:56 · answer #9 · answered by Dagblastit 4 · 0⤊ 0⤋
I have no idea..Hope that helps.
2006-07-25 17:56:43 · answer #10 · answered by Anonymus 2 · 0⤊ 0⤋