Math people please help me !!!! Math people help me?

Question

x= 1,3, 5, 7, 9, 11,13, 15, 17 ...

y= 1,5,13,25,41,61,85,113,145 ...

Form a rule?

Answer 1

x = 2n-1, n is any natural number

y = (x*n)- (n-1)

Answer 2

for finding the general term for x
t(n) = 1 + (n -1) 2
= 1 + 2n - 2
= 2n - 1

for finding the general term for y
the difference between the terms is increasing in the multiples of 4. so it neither fits into the category of A.P. series nor G.P. This is a matter of mere observation. Like if you are standing on 41 and you know which term it is(here it is the fifth term) so you can simply multiply 5 with 4 to get 20 which is the difference between the current term and the next term.

Answer 3

Xn = 2n -1

when n = 1, X1 = 2((1) - 1 = 1
when n = 2 , X2 = 2 (2) - 1 = 3
when n =3, X3 = 2(3) - 1 = 5
and so on

Yn = 2n(n-1) + 1
When n = 1, Y1 = 2x1(1-1) + 1 = 2(0) + 1 = 1
When n= 2, Y2 = 2 x2(2-1) + 1 = 4(1) + 1 = 5
When n= 3, Y3 = 2x3(3-1) + 1 = 6 (2) + 1 = 13
and so on

Answer 4

x:Odd numbers or x+2
y: every 4 multiple.
1+4=5 5+8=13 13+12=25.

Answer 5

x = 1,3,5,7,9,11.....

or nth term = 2n-1

y = 1, 5, 13, 25, ...

or nth term = 4(n-1) + (n-1)th term.
= 2n(n-1)+1

Answer 6

x(n)=x(n-1)+2; n=0,1,2, &x(1)=1;
y(n)=y(n-1)+x(n-1)+x(n);n=0,1,2, &y(1)=1;