An airplane covered 13 miles of its route while decreasing its altitude by 44,000 feet. Find the slope of the airplane's line of descent. Round to the nearest hundredth. [Hint: 1 mi = 5280 feet.]
2006-07-21 13:23:02 · 9 answers · asked by griffin t 1 in Education & Reference ➔ Other - Education
s= o/h c=a/h t=o/a,,,
2006-07-21 13:28:19 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Convert 13 mile into feet. Then create a graph with the vertical axis being altitude and the horizontal access being distance. Then set you intervals on the graph to accomdate the 44,000 feet and whatever the answer is for 13 mile into feet. Then show plot a point that would show the plane before decent and another point showing the plane after decent. Draw a line between the two points.
2006-07-21 13:30:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Convert the 13 miles to feet or the 44,000 feet to miles to get like units.
To avoid fractions, I'll convert 13 miles to 68,640 feet.
Put the plane at 44,000 feet (Y=44,000) at the left of the graph (let X=0) and let it fly 13 miles or 68640 feet to an altitude of 0 feet (y=0).
You know that Slope is Delta Y over Delta X. Or change in Y over change in X. The slope will be a decending slope so you know it is negative. (44,000-0)/(0-68640) or - 44,000/68,640
= -(0.641)
(I'm assuming that you wanted the SLOPE of the line, not the angle of decent. Slope is M or Delta Y over Delta X.)
2006-07-21 13:37:54 · answer #3 · answered by hack_ace 4 · 0⤊ 0⤋
Draw a cartesian coordinate plane... (X axis, y axis).
44,000 feet = approx. 8 miles. (1 mile =5280 ft)
So go 13 miles along the x axis and 8 miles up the y axis... This represents the starting point of the plane's descent. T (0,0) coordinate represents the end of the plane's descent.
Find the slope of the line drawn...
I'm not going to give you the answer. You can handle it from here, I'm sure.
2006-07-21 13:30:16 · answer #4 · answered by hyperhealer3 4 · 0⤊ 0⤋
Its a right angle triangle question. The slope is the hypotenuse. To get that, it is the square root of the sum of the square of the base (distance covered) and the height (altitude lost). So that gives you
(b^2+h^2)^(1/2)
15.44 miles is the slope
2006-07-21 13:33:09 · answer #5 · answered by black_diablo05 2 · 0⤊ 0⤋
make a drawing or diagram.
draw a right triangle with the horizontal side 68,648 ft
(13 miles) and the verticle side 44,000 ft.
The tangent fuction, opposite/adjacent does not require the hypotenuse, or longest side.
the tangent of the descent angle is 44,000/68,648
look it up or divide it and use arctan, that gives you the angle from the tangent.
2006-07-21 13:33:42 · answer #6 · answered by helixburger 6 · 0⤊ 0⤋
3/80 x 42000 = 3/80 x 80 x 525 (80 denominator should be cancelled by skill of the 80 numerator) = 3 x 525 = 1575 in basic terms curious, you need to apply 3 hundred and sixty 5 days calculator on the computer. wish i helped out besides ;)
2016-12-10 13:17:14 · answer #7 · answered by Anonymous · 0⤊ 0⤋
arctan(44000/(13*5280))
= 32.66 degress (downward)
2006-07-21 13:34:52 · answer #8 · answered by Anonymous · 0⤊ 0⤋
http://www.csgnetwork.com/righttricalc.html
Fill it out with your numbers.
2006-07-21 13:35:15 · answer #9 · answered by Chef-in-Training 2 · 0⤊ 0⤋