2006-07-20 12:53:57 · 4 answers · asked by Anonymous in Consumer Electronics ➔ Other - Electronics
It depends on the resistance of the load, and whether the batteries are in series or parallel.
Ohm's law is V = IR where V = voltage, I = current, R = resistance.
So I = V/R, and a 1kOhm load on 3x 1.5V C cells in series would be 3x1.5/1000 = 5mA.
Those figures are approximate; in reality, a cell doesn't give out exactly 1.5 V, and the more current you draw, the lower the voltage will drop, so there's a limit to how much current you can draw even if you have almost no resistance.
Also, as the resistance of the circuit drops, the internal resistance of the batteries themselves becomes relevant, and becomes the limiting factor.
That, and they start to get hot...
2006-07-20 13:01:18 · answer #1 · answered by metavariable 4 · 1⤊ 0⤋
That depends on how much resistance is in the circuit.
I = V(oltage)/R(esistance)
2006-07-20 12:57:15 · answer #2 · answered by knieveltech 3 · 0⤊ 0⤋
About 1.2 at 4.5 volts.
2006-07-20 12:57:05 · answer #3 · answered by Jules G 6 · 0⤊ 1⤋
1.5
2006-07-20 12:55:47 · answer #4 · answered by Anonymous · 0⤊ 1⤋