will 2 4 ohm subs wired in series to a 4 ohm stable have as much out put as 2 8ohms wired parrlell?

Answer 1

You've got the wrong idea.

This might help.

The formula to calculate subs in parallel:

(Rt) = resistance total, sub(#) = each sub or voice coil

Rt = 1 / (1/sub1 + 1/sub2 + 1/sub3 + ...)

The formula for subs in series:

Rt = sub1 + sub2 + sub3 + ...

With this, two 4 ohm subs in series = 8 ohms on a 4 ohm amp will cut power in half.

Two 8 ohms in parallel = 4 ohms. House speakers are 8 ohm, but it's not wise to use house speakers as many amps can EASILY overpower them.

Always match RMS watts of subs with amp per channel as well as impedance(resistance).

For example, a 200 watts RMS X 2 amp will require two 200 watts RMS subs.

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To alchemist_n_tx:

I stand corrected. Are their car amps that are strictly 8 ohm? Otherwise it seems you'd have to get a 1000 watt RMS @ 4 ohm amp just to get 500 watts RMS @ 8 ohms out of it.

Answer 2

2 4 ohm speakers wired in series equals 8 ohms. 2 8ohms speakers paralleled equals 4 ohms. Knowing this, the way the 8ohm subs are wired, they will run the amp at 4ohms giving you the best match.

Answer 3

Alumapro and JL Audio, and Lanzar still make 8-ohm subs, and MTX did not too long ago. As a matter of fact, JL Audio and MTX make 12-ohm single voice coils subs. And to answer your question, two 8-ohm subs will destroy two 4-ohm subs, unless your amp is 2 ohm stable when bridged.

Answer 4

I don't think it is safe for you to be playing with electricity! "out put"? "parrlell"? you probably won't hurt yourself (badly) on a 12V system, but you sound likely to destroy some expensive speakers! Ah, but you're the sort that keeps audio stores in business, just doing your part!

Good luck!