2006-07-20 06:55:52 · 43 answers · asked by mcmillae 3 in Food & Drink ➔ Non-Alcoholic Drinks
totally coke. . they are the original. I'm from atlanta where they started and they have a museum. .
I hate when people only serve pepsi products. Mountain Dew stuff is only better when people are mixing alcohol.
anyway coke all the way, down with the imposter
2006-07-20 06:59:07 · answer #1 · answered by bf 3 · 2⤊ 1⤋
They both taste the same really but ill choose coca its old school Pepsi was made later than cola so i think they just are immitaters they get the defintite boot
2006-07-20 07:15:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Pepsi because I find Coke to be sweeter than Pepsi but that is just my taste buds since my partner feels that Pepsi is sweeter than Coke!!! It all rots your teeth the same way....lol
2006-07-20 06:57:42 · answer #3 · answered by hippiemommy 3 · 0⤊ 0⤋
I prefer Pepsi. It's not as sweet as coke & coke can eat away rust & battery acid off a car battery, imagine what it does to your body! I rarely drink soda but when I do...it's Pepsi. I usually drink coffee & iced tea.
2006-07-20 07:00:20 · answer #4 · answered by lovinlife 3 · 0⤊ 0⤋
Diet Coke tastes really good. Pepsi is too sweet.
2006-07-20 06:58:16 · answer #5 · answered by Shikibeeks 3 · 0⤊ 0⤋
Where's my Diet Dr. Pepper! Ok if I have to pick between those two I'll take a Pepsi, but I won't be happy about it. Coke is too thick! YUCK!
2006-07-20 06:58:53 · answer #6 · answered by flyingbumblebee 5 · 0⤊ 0⤋
Coca-Cola....they produce Sprite!
2006-07-20 06:59:27 · answer #7 · answered by kennydownes187 2 · 0⤊ 0⤋
I prefer Pepsi. Slightly sweeter, and they use Lemon as their Citric Acid base, while Coke uses Orange.
2006-07-20 06:58:20 · answer #8 · answered by racingcowboy58 6 · 0⤊ 0⤋
Pepsi. Coke is too bitter. Pepsi is sweet.
2006-07-20 06:59:03 · answer #9 · answered by One Sly Look 3 · 0⤊ 0⤋
pepsi taste better all the way but mainly id prefer water b/c of the calories in the pop
2006-07-20 06:57:49 · answer #10 · answered by *~BabiGurl~* 3 · 0⤊ 0⤋