2006-07-20 03:59:27 · 11 answers · asked by Apple 1 in Food & Drink ➔ Other - Food & Drink
All RUBBISH!
99's are called that because during the might of Rome & Italy (home of icecream) the emporer had 99 guards vastly more than any other person in authority at the time.
Therefore 99 was seen to be the best of the best, icecream with chocolate was the best of the best hence 99.
2006-07-20 04:21:38 · answer #1 · answered by draytondon 4 · 0⤊ 2⤋
It's based on a misunderstanding of the way that Roman numerals worked. When trying to find a name for their new ice cream, someone saw out that C was the Roman numeral for 100, and I was the numeral for 1. From that, they decided that 99 would be written IC - i.e. 100 minus 1. Say it out loud: Eye-cee. Ice-ee. Icy. See?
Of course, 99 is written XCIX - 100 minus 10, and 10 minus 1. 90 + 9.
Still, no one in the room pointed that out, so the name stuck.
2006-07-20 04:07:27 · answer #2 · answered by Foxie 2 · 0⤊ 0⤋
Well, when icecreams were first invented, they were very expensive. If you brought one with a flake, it would cost 99p (In olden days, this could feed a whole family for a week or if you were a miner a whole year).
2006-07-20 04:05:27 · answer #3 · answered by Ant 1 · 0⤊ 0⤋
They were invented in the USA and cost 99 cents.
2006-07-20 04:20:05 · answer #4 · answered by charlietooo 4 · 0⤊ 0⤋
This was covered on the BBC's "Balderdash and Piffle" programme. Consult the archives.
2006-07-20 04:04:03 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Because they used to cost 99p
2006-07-20 04:02:48 · answer #6 · answered by ALEX L 2 · 0⤊ 0⤋
they are supposed to be 99p...shame they are closer to 99 quid these days huh?
2006-07-20 04:03:47 · answer #7 · answered by Anonymous · 0⤊ 0⤋
cos thats how many a fatty can eat
2006-07-20 04:59:10 · answer #8 · answered by markhatter 6 · 0⤊ 0⤋
cos they cost 99p or should do
2006-07-20 04:29:17 · answer #9 · answered by uuhyufcrersx 2 · 0⤊ 0⤋
good question...let me know wen u find out
2006-07-20 04:03:04 · answer #10 · answered by whistleblower 3 · 0⤊ 0⤋