this is how i learned it!
X = -B[the opposite of B] plus[+] or minus[-] the square root of B squared minus[-] 4 times A times C [4*a*c] divided by [on top of/over] B times a
2006-07-20 02:02:50
·
answer #1
·
answered by Anonymous
·
6⤊
1⤋
X=(b^2+or - (4ac)^1/2)/2a
the formula for the roots (2) Of A 2nd degree or "quadratic" equation
ax^2+bx+c=0
2006-07-20 02:08:58
·
answer #2
·
answered by helixburger 6
·
0⤊
0⤋
The formulae is ::
ax+bx+c = 0
2006-07-20 02:13:44
·
answer #3
·
answered by akm_rocking 2
·
0⤊
0⤋
fuilui213 got it.
negative B, plus or minus the square root of (Bsquared minus 4xAxC) all divided by 2A
2006-07-20 02:08:26
·
answer #4
·
answered by gabluesmanxlt 5
·
0⤊
0⤋
(-b) plus or minus the square root of b^2-4ac...all divided by 2a
2006-07-20 02:05:28
·
answer #5
·
answered by fuilui213 6
·
0⤊
0⤋
it'll tell you about it on this website http://mathworld.wolfram.com/QuadraticFormula.html I used to know it but now that it's summer I've become brain dead, everything will comeback to me during school.
2006-07-20 02:09:03
·
answer #6
·
answered by Anonymous
·
0⤊
0⤋
The second answer is correct.
2006-07-20 02:08:50
·
answer #7
·
answered by Pi R Squared 7
·
0⤊
0⤋
it goes like this:
2006-07-20 02:41:51
·
answer #8
·
answered by sandeepan88 1
·
0⤊
0⤋